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2 years ago

In a real isothermal expansion, the temperature of the surroundings must be________the temperature of the gas.

Physics

1 answer:

Lady_Fox [76]2 years ago

7 0

Must be isolated from the temperature of the gas

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What is the horse power of an electric motor which can do by 1250 joule of work in 5 seconds

Ksju [112]

1250 J in 5 sec= 250 Joule(s) per second (1250/5 0

250 Joules per second = 250 Watts ( 1J/s = 1 Watt per definition)

250 Watts output = 250/0.65 efficiency = 384 Watts input

1 Horsepower = 732 Watts

Motors 1 Horsepower and under are made in certain step sizes like

3/4 , 1/2 , 1/3, 1/4, 1/16 1/20 of a Horsepower.

3/4 Horsepower is 549 Watts

1/2 Horsepower is 366 Watts

so you need to 3/4 horsepower motor to achieve 1250 J of work in 5 seconds.

5 0

2 years ago

Which of the following describes the principle of conservation of charge?

grigory [225]

Answer: The statement "The charge cannot be created or destroyed describes the principle of the conservation of charge".

Explanation:

According to the conservation of charge, the charge can neither be created nor destroyed. It can be transferred from one system to another.

In an isolated system, the total electric charge remains constant. The net quantity of electric charge is always conserved in the universe.

Therefore, "the charge cannot be created or destroyed" describes the principle of the conservation of charge.

7 0

3 years ago

A motorcycle and a police car are moving toward one another. The police car emits sound with a frequency of 523 Hz and has a spe

Firdavs [7]

To solve this problem it is necessary to apply the concepts related to Dopler's Law. Dopler describes the change in frequency of a wave in relation to that of an observer who is in motion relative to the Source of the Wave.

It can be described as

$f = \frac{c\pm v_r}{c\pm v_s}f_0$

c = Propagation speed of waves in the medium

$v_r$ = Speed of the receiver relative to the medium

$v_s$ = Speed of the source relative to the medium

$f_0 =$ Frequency emited by the source

The sign depends on whether the receiver or the source approach or move away from each other.

Our values are given by,

$v_s = 32.2m/s \rightarrow$ Velocity of car

$v_r = 14.8 m/s \rightarrow$ velocity of motor

$c = 343m/s \rightarrow$ Velocity of sound

$f_0 = 523Hz \rightarrow$ Frequency emited by the source

Replacing we have that

$f = \frac{c + v_r}{c - v_s}f_0$

$f = \frac{343 + 14.8}{343 - 32}(523)$

$f = 601.7Hz$

Therefore the frequency that hear the motorcyclist is 601.7Hz

8 0

3 years ago

Question is attatched!

lina2011 [118]

All it does is lets him pull in a more convenient direction to raise the load. It has no effect on the required force.

4 0

3 years ago

Star A and Star B have measured stellar parallax of 1.0 arc second and 0.75 arc second, respectively. Which star is closer? How

zhuklara [117]

Answer:

Star A is closer than Star B

Explanation:

As we know that in parallax method of distance measurement the angle subtended by the star when it covers a distance of one Parsec arc length, it is known as parallax angle

Here we can say

$angle = \frac{1 Parsec}{distance}$