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Tcecarenko [31]
3 years ago
12

Two blocks of ice, one four times as heavy as the other, are at rest on a frozen lake. A person pushes each block the same dista

nce d. Ignore friction and assume that an equal force F is exerted on each block.
Now assume that both blocks have thesame speed after being pushed with the same force F. What can be said about the distances the two blocks arepushed?

A. The heavyblock must be pushed 16 times farther than the lightblock.
B. The heavyblock must be pushed 4 times farther than the lightblock.
C. The heavyblock must be pushed 2 times farther than the lightblock.
D. The heavytblock must be pushed the same distance as the lightblock.
E. The heavyblock must be pushed half as far as the light block.
Physics
1 answer:
qaws [65]3 years ago
4 0

Answer:b

Explanation:

Given

mass of heavy object is 4m

mass of lighter object is m

A person pushes each block  with same force F

According to Work Energy theorem Change in kinetic energy of object is equal to Work done by all the object

As launching velocity is same for both the object so heavier mass must possess greater kinetic energy . For same force heavier mass must be pushed 4 times farther than the light block .

\Delta (K.E.)_H=\frac{1}{2}(4m)v^2

\Delta (K.E.)_L=\frac{1}{2}(m)v^2

\Delta K.E.=F\times d

So the correct option is b

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nika2105 [10]

Answer: hello your question is poorly written attached below is the complete question

P(  ³₂He₊ )  at ground state = 1

Explanation:

<u>Determine the probability that the  3He atom is in its ground state after decay</u>

From the attached solution the coulomb interaction of ( ³₂He)  is double that of H³ . given that coulomb interaction is attractive ( -ve ) this will make  the product to become more stable hence the product ( ³₂He₊ ) will be gotten at the ground state

i.e. P(  ³₂He₊ )  at ground state = 1

attached below is a detailed solution

5 0
3 years ago
A cue ball has a mass of 0.5 kg. During a game of pool, the cue ball is struck and now has a velocity of 3 . When it strikes a s
photoshop1234 [79]

Answer: 3 m/s

Explanation:

We can solve the problem by using the law of conservation of momentum: during the collision between the two balls, the total momentum of the system before the collision and after the collision must be conserved:

p_i = p_f

The total momentum before the collision is given only by the cue ball, since the solid ball is initially at rest, therefore

p_i = m_c u_c = (0.5 kg)(3 m/s)=1.5 kg m/s

So, the final total momentum will also be

p_f = 1.5 kg m/s

And the total momentum after the collision is given only by the solid ball, since the cue ball is now at rest, therefore:

p_f = m_s v_s

from which we find the velocity of the solid ball

v_s = \frac{p_f}{m_s}=\frac{1.5 kg m/s}{0.5 kg}=3 m/s

8 0
3 years ago
Read 2 more answers
An apple is held completely submerged just below the surface of water in a container. The apple is then moved to a deeper point
kodGreya [7K]

Answer:

c- the same

Explanation:

There will be apparent  reduction in the weight of the apple due to buoyant force acting on it in upward direction . The magnitude of upward directing buoyant force will be equal to weight of water displaced . The weight of displaced water will remain same if it is completely submerged in water and it is moved from one point to another inside water. So in the given two cases , weight of displaced water will same . Hence the buoyant force too will remain same . Hence the apparent weight too will be same .

So force required to hold apple at deeper point inside water will remain same.

6 0
3 years ago
The density of un-set concrete is 2.40 x 10 3 kg/m 3 . When a block with volume 0.0708 m 3 is submerged in the liquid, a force o
Alenkinab [10]

Answer:

The answer to your question is weight =  1667 N  

Explanation:

Data

density = 2.40 x 10³ kg/m³

volume = 0.0708 m³

Force = 66.7 N

weight of the block = ?

- Formula

  density = mass / volume

- Solve for mass

   mass = density x volume

-Substitution

   mass = (2.40 x 10³)(0.0708)

-Result

   mass = 169.92 kg

-Calculate the weight of the body

   weight = mass x gravity

-Substitution

   weight = 169.92 x 9.82

-Simplification

   weight = 1666.9 N ≈ 1667 N        

6 0
3 years ago
Your teacher had not exercised since the beginning of distance learning. She decided to exercise by walking in the park. The par
Lesechka [4]

A) 6000 m

B) 0 m

C) 3.33 m/s

D) 0 m/s

Explanation:

a)

In physics, distance is a scalar quantity that represents the total length of the path covered by an object during its motion.

Being a scalar quantity, it has no direction, but only a magnitude (so, a number + its units).

The distance covered by a body can be calculated by adding together all the lengths of all the motion of the body.

In this problem, the teacher walks in the partk, starting at position A, then walking around the park 5 times and returning to the original position.

The park has a rectangular shape 200 m x 400 m, so the perimeter of the park is:

p=200+400+200+400=1200 m

The teacher covers the perimeter 5 times, so the total distance she covered is:

d=5p=5\cdot 1200 =6000 m

B)

Displacement, instead, is a vector quantity that connects the initial position to the final position of the motion of an object.

Being a vector, it has both  a magnitude and a direction, where:

- The magnitude is equal to the length of the vector, so it corresponds to the shortest distance in a straight line between the initial and final position

- The direction goes from the initial position to the final position

In this problem:

- The teacher starts her motion at position A

- The teacher ends her motion at position A

So, the distance between the initial and final position is zero:

d=x_A -x_A = 0

And therefore, the displacement is zero.

C)

The average speed of an object is a scalar quantity telling us how fast an object is moving, regardless of its direction of motion.

Being a scalar quantity, it has only a magnitude, and no direction.

The average speed is given by the equation:

v=\frac{d}{t}

where

d is the distance covered by the object

t is the time elapsed

In this problem we have:

d = 6000 m is the distance covered by the teacher

t = 30 min = 1800 s is the time elapsed

Therefore, the average speed is:

v=\frac{6000}{1800}=3.33 m/s

D)

The average velocity of an object is a vector quantity telling us how fast an object is moving but also its direction of motion.

Being a vector, it has both a magnitude and a direction, where:

- The direction corresponds to the direction of the displacement

- The magnitude is given by the formula:

v=\frac{d}{t}

where

d is the displacement of the object

t is the time elapsed

In this problem:

d = 0 is the displacement of the teacher

t = 1800 s is the time elapsed

Therefore, the average velocity is zero:

v=\frac{0}{1800}=0 m/s

7 0
3 years ago
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