Answer:
The next three terms are 54, 162, 486
Step-by-step explanation:
Exponential sequences you multiply to find the next term
6 x 3 = 18 (to find the next term you can multiply the previous term by 3)
18 x 3 = 54
54 x 3 = 162
162 x 3 = 486
2000 soldiers stand in a row. Beginning from the left, each soldier calls out a number, 1, 2, 3, 1, 2, 3, 1, 2, 3, 1, 2, 3, and
Cloud [144]
Answer:
The number of soldiers that call out a number 3 is 666 soldiers
Step-by-step explanation:
The parameters given are;
Number of soldiers = 2000
Soldiers calling from the left = 1, 2, 3,.....
Soldiers calling from the right = 1, 2, 3,.....
Therefore, since the number soldiers calling out the number 3 are 1 in 3 from the left and 1 in 3 from the right, we split the soldiers into 2 groups of 1000, with one group calling from left and the other group calling from the right;
The number of 3s in called out in the first group from the left is therefore;
1000/3 = 333.33 which is 333 soldiers or from the 3rd soldier to the 999th soldier
Similarly the number of 3s called out from the second group = 333
Hence the total number of soldiers that call out a number 3 = 333 + 333 = 666 soldiers.
Answer:
see below
Step-by-step explanation:
I enter the equation into a graphing calculator and let it do the graphing.
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If you're graphing this by hand, you start by looking for the parent function. Here, it is |x|. That has a vertex of (0, 0) and a slope of +1 to the right of the vertex and a slope of -1 to the left of the vertex.
Here, the function is multiplied by -3/2, so will open downward and have slopes of magnitude 3/2 (not 1). The graph has been translated 5 units upward, so the vertex is (0, 5).
I'd start by plotting the vertex point at (0, 5), then identifying points with slope ±3/2 either side of it. To the left, it is left 2 and down 3 to (-2, 2). The points on the right of the vertex are symmetrically located about the y-axis, so one of them will be (2, 2).
Of course, you don't plot any function values for x > 4.
If so then add 6, then divide the 7 off the a
