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drek231 [11]
3 years ago
10

Which of the following is the complete list of roots for the polynomial function (x)= (x2+bx+3)(x+6x+13)?

Mathematics
1 answer:
shusha [124]3 years ago
4 0

Answer:

if i got you question right then its x=(-13/7) x=(-3/(2+b))

Step-by-step explanation:

to find the roots you need to make it equal to 0.

(x+6x+13)(2x+bx+3) =0

(7x+13)((2+b)x+3) =0

now there are 2 cases:

-> 7x+13=0 7x=(-13) x=(-13/7) solved

-> (2+b)x+3=0 (2+b)x=(-3) x=(-3/(2+b)) solved

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The required steps are explained below to convert the quadratic function into a perfect square.

<h3>What is the parabola?</h3>

It's the locus of a moving point that keeps the same distance between a stationary point and a specified line. The focus is a non-movable point, while the directrix is a non-movable line.

Let the quadratic function be y = ax² + bx + c.

The first step is to take common the coefficient of x². We have

\rm y = a \left (x^2 + \dfrac{b}{a}x \right) + c

Add and subtract the half of the square the coefficient of x,

\rm y = a \left (x^2 + \dfrac{b}{a}x + \dfrac{b^2}{4a^2} \right) - a \times \dfrac{b^2}{4a^2} + c

Then we have

\rm y = a \left (x + \dfrac{b}{a} \right)^2 - \dfrac{b^2}{4a} + c

These are the required step to get the perfect square of the quadratic function.

More about the parabola link is given below.

brainly.com/question/8495504

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