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3 years ago

I need help ASAP (determine the function)

Mathematics

1 answer:

frosja888 [35]3 years ago

5 0

The answer is C because there are arrow at the end of each line meaning it goes on forever

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Solve for x. 2x−45=x+4 Enter your answer in the box. x =

nata0808 [166]

2x - 45 = x +4

Add 45 to each side:

2x = x + 49

Subtract 1x from each side:

x = 49

7 0

3 years ago

PLEASE look at photo and help!

VMariaS [17]

It would be a a 6 by 5 inch rectangle, since the height is 6in and the width is 5in. Those are what would make up the cross section.

6 0

3 years ago

What is the equation of the axis of symmetry do the quadratic function f(x) = -(x+4) (x-1)

miv72 [106K]

9514 1404 393

Answer:

x = -3/2

Step-by-step explanation:

The zeros of the function are the values of x that make the factors zero:

x = -4, x = 1

The axis of symmetry is the vertical line halfway between these zeros.

x = (-4 +1)/2 = -3/2

The equation of the axis of symmetry is x = -3/2.

8 0

3 years ago

Alright have posted it now.

Mrrafil [7]

Hi again! so vertical angles are angles that are across from eachother, so it would be 5 and 7 and 6 and 8

7 0

3 years ago

Kathy is fencing in her yard that has an area of 800 square feet. Her yard is in the shape of a rectangle where the length is 60

anygoal [31]

Answer:

The dimensions of the yard are W=20ft and L=40ft.

Step-by-step explanation:

Let be:

W: width of the yard.

L:length.

Now, we can write the equation of that relates length and width:

$L=5W-60$ (Equation #1)

The area of the yard can be expressed as (using equation #1 into #2):

$Area=W*L=W*(5W-60)$ (Equation #2)

Since the Area of the yard is $800 ft^2$ , then equation #2 turns into:

$800=W*(5W-60)$

Now, we rearrange this equation:

$800=W*(5W-60)//800=5W^2-60W//5W^2-60W-800=0$

We can divide the equation by 5 :

$W^2-12W-160=0$

We need to find the solution for this quadratic. Let's find the factors of 160 that multiplied yields -160 and added yields -12. Let's choose -20 and 8, since $(-20)*8=160$ and $-20+8=-12$ . The equation factorised looks like this:

$(W-20)(W+8)=0$

Therefore the possible solutions are W=20 and W=-8. We discard W=-8 since width must be a positive number. To find the length, we substitute the value of W in equation #1:

$5*20-60=40$

Therefore, the dimensions of the yard are W=20ft and L=40ft.

7 0

3 years ago