Please help asap . i will give brainliest -elena:)

2.

victus00 [196]

Answer:

With a vertex (h, k) at (0, 3) and given that a = -3, then the equation of this parabola in vertex form is as follows:

y = a(x - h)2 + k

y = -3(x - 0)2 + 3

y = -3x2 + 3

Step-by-step explanation:

7 0

3 years ago

In Exercises 27 and 28, find the domain of the function

Natali5045456 [20]

Question 27

The graph on question 27 indicates that there are three points with the locations such as:

(2, 6)

(4, 12)

(6, 18)

In other words, there are three points that lie on the graph with the x-values such as:

{(2, 6), (4, 12), (6, 18)}

We know that the domain includes the set of x-values.

Hence, the domain of the function is:

Domain: {2, 4, 6}

Since the points are not connected between them. In other words, there is not a continuous line.

Thus, the function represented on the graph has a discrete domain.

Question 28

The graph on question 27 indicates that the line segment with the end-points (0, 25) and (7, 20).

Since there is a continuous line between the points from x = 0 to x = 7.

Thus, the domain of the line function is:

Domain: {0, 1, 2, 3, 4, 5, 6, 7}

As the line segment is a continuous line. Thus, the domain is continuous.

3 0

2 years ago

An isosceles trapezoid is a quadrilateral with two congruent legs and a pair of parallel bases. Prove the base angles of an isos

Firdavs [7]

Check the picture below.

now, we know that the slanted legs are congruent, since it's an isosceles trapezoid, we also know that the bases are the parallel sides, so, the "altitude" or distance from those bases are the same length, for each of those triangles in the picture.

now, the bases are parallel, that means the altitude segment is perpendicular to the base, the longest side at the bottom, so, we end up with a right-triangle that has a Hypotenuse and a Leg, equal to the other triangle's.

thus, by the HL theorem for right triangles, both of those triangles are congruent, and if the triangles are congruent, all their sides are also, including the ones on the base.