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3 years ago

What is the common ratio of the geometric sequence 16, 24, 36, 54, ...? 1 8

Mathematics

1 answer:

timurjin [86]3 years ago

5 0

The common ratio in the geometric sequences 2
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What is the instantaneous rate of change of f(x)=xe^x-(x 2)e^(x-1) at x=0 ?

lozanna [386]

You have to derive for a multiplication in both terms:
=e^x+xe^x-(e^x-1 + (x-2)e^x-1) now apply distributive property in the last term:
=e^x+xe^x+e^x-1-xe^x-1 now replace each x by 0 (x=0)
=1 + 0 + e^-1 + 0 = 1+ e^-1 = 1.3679

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3 years ago

Find the next number in the following sequences

spin [16.1K]

Not sure about the others but
b) 8,192
the pattern is multiplying by 8 each time for b

4 0

2 years ago

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If x = 9 units and h = 4 units, then what is the area of the triangle shown above?

Aleks04 [339]

Answer:

Step-by-step explanation:

The area of triangle is b*h/2

so it will be 36/2 which will be 18

Please mark as Brainliest

7 0

2 years ago

Find the area of a trapezium whose parallel sides are 28.7 cm and 22.3 cm and distance between parallel sides is 16 cm.

puteri [66]

Given:

The parallel sides of a trapezium are 28.7 cm and 22.3 cm.

The distance between parallel sides is 16 cm.

To find:

The area of a trapezium.

Solution:

The area of the trapezium is:

$A=\dfrac{a+b}{2}h$

Where, $a,b$ are parallel sides and $h$ is the vertical distance between the parallel sides.

Putting $a=28.7, b=22.3,h=16$ in the above formula, we get

$A=\dfrac{28.7+22.3}{2}\times(16)$

$A=\dfrac{51}{2}\times 16$

$A=51\times 8$

$A=408$

Therefore, the area of the trapezium is 408 square cm.

4 0

3 years ago

If f(x) = x-6 and g(x)= 1/2x (x+3), find g(x) * f(x)

sertanlavr [38]

Answer:

Final answer is $g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}$ .

Step-by-step explanation:

given functions are $f(x)=x-6$ and $g\left(x\right)=\frac{1}{2x\left(x+3\right)}$ .

Now we need to find about what is the value of $g\left(x\right)*f\left(x\right)$ .

$g\left(x\right)*f\left(x\right)$ simply means we need to multiply the value of $f(x)=x-6$ and $g\left(x\right)=\frac{1}{2x\left(x+3\right)}$ .

$g\left(x\right)\cdot f\left(x\right)=\frac{1}{2x\left(x+3\right)}\cdot\left(x-6\right)$

$g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}$

Hence final answer is $g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}$ .

5 0

3 years ago