It doesn't matter what number the negative sign is on. What matters is if the negative sign is there at all.
1) A & B
2) C & D
6x+6=8x
-6x -6x
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6=2x
6 divided by 2
x=3
A triangle's angles will always equal up to 180. Since you already have to of the angles, you will add them up together. 30+20=50. Then, you take 180 and subtract it by the sum of the two previous angles. 180-50=130. Now you know the last angle is 130. You also know that the missing angle is also 130. The reason for that is because the two angles are the exact same if you look at it.
The answer is just half of the first fraction which is 3/2
Answer:
P and Q are two points on the line x-y+1=0 and are at a distant of 5 units from the origin. Find the area of triangle POQ.
Step-by-step explanation:
P and Q are the intersection points of
x-y+1 = 0 and the circle x^2 + y^2 = 25
sub y = x+1 into the circle
x^2 + (x+1)^2 = 25
x^2 + x^2 + 2x + 1 - 25 = 0
x^2 + x - 12 = 0
(x+4)(x-3) = 0
x = 3 or x = -4
y = 4 or y = -3
so P(3,4) and Q(-4,3) are our two points
Height of triangle.
h = |0 - 0 + 1|/√2 = 1/√2
PQ = √( (-7)^2 + 1^2) = √50 = 5√2
area POQ = (1/2)(1/√2)(5√2) = 5/2 square units
hope this helped