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3 years ago

After evaluating Olya’s monthly budget, which of the following would not be an option to help reduce her debt?

Mathematics

2 answers:

Masteriza [31]3 years ago

8 0

Answer with explanation:

As , Olya want to pay her debt after spending money for her monthly budget, the following precaution can be taken by Olya for paying her Debt,

a: Olya could spend less on entertainment each month and put the money towards her credit card payment.

b: Olya could skip a month or two paying for her school loan and put the money towards her credit card debt.

c: Olya could try to save money on her utility bills by investigating money saving plans offered by the utility company.

⇒The following is not a wise decision to reduce her debt

Option D: Olya could spend less on food each month and put the money towards her credit card payment.

Why , i am saying this because if she will not take diet which is full of All the nutritional components , her mind will not work with full capacity , and she will not be able to give her 100% in work , due to that she will suffer from deficiency deseases.So, she should spend sufficient amount of her income on food and spend less money on other things like entertainment, Sports, Music,Mobile, for paying her debt.

frosja888 [35]3 years ago

6 0

The answer is B.<span>Olya could skip a month or two paying for her school loan and put the money towards her credit card debt. just took the test..</span>

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The maximum value of the function: f(x)= -5 x ^2 +30x-200 is?

VARVARA [1.3K]

Answer:

$\displaystyle - 155$

Step-by-step explanation:

we are given a quadratic function

$\displaystyle f(x) = - 5 {x}^{2} + 30x - 200$

we want to figure out the minimum value of the function

to do so we need to figure out the minimum value of x in the case we can consider the following formula:

$\displaystyle x _{ \rm min} = \frac{ - b}{2a}$

the given function is in the standard form i.e

$\displaystyle f(x) = a {x}^{2} + bx + c$

so we acquire:

b=30
a=-5

thus substitute:

$\displaystyle x _{ \rm min} = \frac{ - 30}{2. - 5}$

simplify multiplication:

$\displaystyle x _{ \rm min} = \frac{ - 30}{ - 10}$

simply division:

$\displaystyle x _{ \rm min} = 3$

plug in the value of minimum x to the given function:

$\displaystyle f (3)= - 5 {(3)}^{2} + 30.3 - 200$

simplify square:

$\displaystyle f (3)= - 5 {(9)}^{} + 30.3 - 200$

simplify multiplication:

$\displaystyle f (3)= - 45 + 90- 200$

simplify:

$\displaystyle f (3)= - 155$

hence,

the minimum value of the function is -155

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3 years ago

Find the 75th term of the arithmetic sequence -17, -13, -9....

Sphinxa [80]

Answer:

The 75th term of the arithmetic sequence -17, -13, -9.... is:

$a_{75}=279$

Step-by-step explanation:

Given the sequence

$-17, -13, -9....$

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

computing the differences of all the adjacent terms

$-13-\left(-17\right)=4,\:\quad \:-9-\left(-13\right)=4$

The difference between all the adjacent terms is the same and equal to

$d=4$

The first element of the sequence is:

$a_1=-17$

now substitute $d=4$ and $a_1=-17$ in the nth term of the sequence

$a_n=a_1+\left(n-1\right)d$

$a_n=4\left(n-1\right)-17$

$a_n=4n-21$

Now, substitute n = 75 in the $a_n=4n-21$ sequence to determine the 75th sequence

$a_n=4n-21$

$a_{75}=4\left(75\right)-21$

$a_{75}=300-21$

$a_{75}=279$

Therefore, the 75th term of the arithmetic sequence -17, -13, -9.... is:

$a_{75}=279$

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