Answer:
y=1/5x-31/5 (or y=0.2x-6.2 in decimals)
Step-by-step explanation:
x=5y-8 (original equation)
x+8=5y <u>(Addition Property of Equality)</u>
1/5x+8/5=y <u>(Division Property of Equality, </u><u>slope </u><u>of </u><u><em>original equation </em></u><u>is </u><u>1/5</u><u>)</u>
<u />
y-y1=m(x-x1) <u>(point-slope formula)</u>
y-(-5))=1/5(x-(6)) <u>(plug in the slope that was found earlier and the point given in the question)</u>
y+5=1/5(x-6)
y+5=1/5x-6/5 (Distributive Property of Multiplication) Note: 5 = 25/5
<u>y=1/5x-31/5</u> (Subtraction Property of Equality, and there's your answer)
<u>y=0.2x-6.2</u><em> </em>(This is the same answer, but written with decimals)
Answer:
the answer is the last one
Step-by-step explanation:
so the answer is d
![\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ h=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{65}t](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Binitial%20velocity%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20~~~~~~%5Ctextit%7Bin%20feet%7D%20%5C%5C%5C%5C%20h%28t%29%20%3D%20-16t%5E2%2Bv_ot%2Bh_o%20%5Cend%7Barray%7D%20%5Cquad%20%5Cbegin%7Bcases%7D%20v_o%3D%5Cstackrel%7B%7D%7B%5Ctextit%7Binitial%20velocity%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h_o%3D%5Cstackrel%7B%7D%7B%5Ctextit%7Binitial%20height%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h%3D%5Cstackrel%7B%7D%7B%5Ctextit%7Bheight%20of%20the%20object%20at%20%22t%22%20seconds%7D%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20h%3D-16t%5E2%2B%5Cstackrel%7B%5Cstackrel%7Bv_o%7D%7B%5Cdownarrow%20%7D%7D%7B65%7Dt)
now, take a look at the picture below, so for 2) and 3) is the vertex of this quadratic equation, 2) is the y-coordinate and 3) the x-coordinate.


Answer:
3) y = 50 * 2¹²ˣ
2) y = 80 * 2⁸ˣ
Step-by-step explanation:
1 day = 24 hours
Number of 2-hour periods in 1 day = 24 ÷ 2 = 12
Number of 3-hour periods in 1 day = 24 ÷ 3 = 8
Colby's experiment:
y = 50 * 2¹²ˣ
Jaquan's experiment:
y = 80 * 2⁸ˣ
Answer:
quadrilateral
Step-by-step explanation: