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denis23 [38]
3 years ago
12

8^2x+1=4^1-x what is the solution

Mathematics
1 answer:
Lapatulllka [165]3 years ago
6 0

Step-by-step explanation:

8 ^{2x + 1}=   {4}^{1 - x}

({2}^{3})^{2x + 1}   = ({2}^{2})^{1 - x}

2^{6x + 3}  =  {2}^{2 - 2x}

6x + 3 = 2 - 2x

6x + 2x = 2 - 3

8x =  - 1

x =   - \frac{1}{8}

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Answer:

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