Question

8^2x+1=4^1-x what is the solution

Answer 1

Step-by-step explanation:

$8 ^{2x + 1}= {4}^{1 - x}$

$({2}^{3})^{2x + 1} = ({2}^{2})^{1 - x}$

$2^{6x + 3} = {2}^{2 - 2x}$

$6x + 3 = 2 - 2x$

$6x + 2x = 2 - 3$

$8x = - 1$

$x = - \frac{1}{8}$