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pochemuha
3 years ago
6

Create an equation to solve for x, then solve to find its value.

Mathematics
1 answer:
katrin [286]3 years ago
8 0

Answer:

btnhyjum6666666i-n,,,,,,,,,,,

Step-by-step explanation:

vwgbthyjuuuuuuuuuu'

lJhbgvft

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Sergey is mixing cement, sand, and stone to make concrete. In order to make 8 buckets of concrete, he must use 3 1 4 buckets of
il63 [147K]

So first you beg your mom to seduce your teacher then all you needa do is sit back in that class

7 0
3 years ago
The angles of a triangle are 80°, 2x + 2°, and 5x°. What is the value of x? Enter your answer in the box. x =
Assoli18 [71]
Angles in triangle add up to 180°, thus to solve for the value of x, we add up our angles and equate it to 180.
80+(2x+2)+(5x)=180
simplifying this we have:
80+2x+2+5x=180
80+2+5x+2x=180
82+7x=180
7x=180-82
7x=98
x=98/7
x=14
thus the value of x is:
14°
7 0
4 years ago
If correct I’ll give brainlist
melamori03 [73]

Answer:

-2/3

Step-by-step explanation:

rate of change = slope = rise/run

rise/run = -2/3

8 0
3 years ago
Tank is a car salesman at EH Auto Dealer. The data below
Licemer1 [7]

Answer:

\begin{array}{cc}{Cars} & {Months} & {28} & {3} & {29} & {3} & {30} & {1} & {31} & {2} \ \end{array}

Step-by-step explanation:

Given

<u>Data:</u>

29\ 30\ 29

29\ 31\ 28

28\ 31\ 28

Required

Construct a frequency table

From the given data, we have:

<em>28 occurs 3 times</em>

<em>29 occurs 3 times</em>

<em>30 occurs 1 time</em>

<em>31 occur 2 times</em>

Hence, the frequency table is:

\begin{array}{cc}{Cars} & {Months} & {28} & {3} & {29} & {3} & {30} & {1} & {31} & {2} \ \end{array}

6 0
3 years ago
For what values of k the relation R:{(k2 , 5), (3k, 6)} is not a function?
n200080 [17]
<h3>Answer:  k = 0 or k = 3</h3>

Explanation:

If you have repeated x values, then you wont have a function. For example, the points (1,5) and (1,6) mean we don't have a function since the input x = 1 leads to multiple outputs y = 5 and y = 6 simultaneously. For a function to be possible, we must have any input lead to exactly one output only.

What we do is set the x coordinates (k^2 and 3k) equal to each other and solve for k

k^2 = 3k

k^2-3k = 0

k(k-3) = 0 .... factoring

k = 0 or k-3 = 0 .... zero product property

k = 0 or k = 3

If k = 0, then (k^2,5) becomes (0,5). Also, (3k,6) becomes (0,6). The two points (0,5) and (0,6) mean the graph fails the vertical line test.

Similarly, if k = 3, then (k^2,5) becomes (9,5) and (3k,6) = (9,6). Another vertical line test failure happens here to show we don't have a function.

7 0
3 years ago
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