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liberstina [14]
3 years ago
13

Janelle is at the store and can't decide whether to buy steak for dinner or bring home pizza. To get a quick response from her p

artner, which channel of communication would be best?
Computers and Technology
1 answer:
dalvyx [7]3 years ago
4 0

Answer:

The correct answer to the following question will be "Text message".

Explanation:

  • Text messaging would be the method of writing and transmitting written messages, usually alphabetical and numerical symbols or characters, between two or even more operators of mobile phones and tablets, laptops/desktops, or other compatible computers.
  • You can send texts over a mobile phone network or send them via a Connection to the internet as well.

Hence, text messages would be the best channel of communication.

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Suppose the length of each packet is L bits. Also, assume the path from a server to a client includes N links each of rate R (i.
nignag [31]

Answer:

Attached is the solution

3 0
3 years ago
Write a program, NumberStatistics.java, that reads an unspecified number of integers. The program ends with the input 0. The pro
Lerok [7]

Answer:

Following are the program, which can be below:

import java.util.*; //defining header file

public class NumberStatistics  //defining class NumberStatistics

{

public static void main(String[] arc) //defining main method

{

int total_number=0,max_val=0,min_val=0,neg_val=0,pos_val=0,neg_count=0,pos_count=0,x; //defining variables

Scanner ox= new Scanner(System.in); //creating Scanner class Object

System.out.println("Enter positive and negative value with sign and when complete inter 0:"); //print message  

x= ox.nextInt(); //input value from user

while(x!=0) //defining loop to check input value is 0

{

total_number++; // increment value

if(total_number == 1)  //defining conditional statement to check minimum and maximum value

{

max_val = x; //assign value in max  

min_val = x;//assign value in min

}

else  //defining else block

{

if(max_val < x) //check maximum value

{

max_val = x; //assign maximum value

}

if(min_val > x) //check minimum value

{

min_val = x; //assign minimum value

}

}

if(x > 0) //input values  

{

pos_count++; //count positive value

pos_val+=x; // add positive values

}

else  

{

neg_count++;//count negative value

neg_val+=x; // add negative values

}

x = ox.nextInt(); //input values

}

// defining conditionl statement

if(total_number != 0)  // defining if block to print all value

{

System.out.println("positive value average= "+(pos_val/(double)pos_count));

System.out.println("negative values Average= "+(neg_val/(double)neg_count));

System.out.println("all values average= "+(pos_val+neg_val)/(double)total_number);

System.out.println("maximum value = "+max_val+"\n"+" minimum value = "+min_val);

}

else  

{

System.out.println("no positive values found");

System.out.println("no negative values found");

}

}

}

Output:

Enter positive and negative value with sign and when complete inter 0:

12

8

04

22

-22

-5

9

0

positive value average= 11.0

negative values Average= -13.5

all values average= 4.0

maximum value = 22

minimum value = -22

Explanation:

The Description of the above java program can be described as follows:

  • In the above code first we import the package for user input, then defines the variable "total_number,max_val,min_val,neg_val,pos_val,neg_count, pos_count,x" to store the value prints its value.
  • In the next step, a scanner class object is created for user input and defines a while loop, that checks input value isn't equal to 0, inside the loop a conditional statement defines that cont and calculates all positive, negative, and all values addition.
  • At the another conditional statement is defines, that prints all value average, and also prints maximum, minimum value.
6 0
3 years ago
all of the following are new technology-related trends in mis except: group of answer choices the mobile digital platform. iot.
Bess [88]

The option that is note a new technology-related trends in MIS is co-creation of business value.

<h3>Technology and Management Information System:</h3>

Technology and Management Information System is known to be a term that connote the way a person can know or understand data that is obtained from a lot of units and departments of an organization.

Note that It can be used in the area of integration with other types of technology and as such, The option that is note a new technology-related trends in MIS is co-creation of business value.

Learn more about  business value from

brainly.com/question/25528419

#SPJ1

5 0
2 years ago
Write a program roman which converts numbers from decimal notation into Roman numerals. roman takes a single argument, a string
MaRussiya [10]

Answer:

// Program is written in C++ programming language

/ Comments are used for explanatory purpose

// Program starts here

#include<bits/stdc++.h>

using namespace std;

//Declare a function named value to represent the symbols of Roman Numerals

int value(char xy)

{

if (xy == 'I') { return 1; }

if (xy == 'V') { return 5; }

if (xy == 'X') { return 10; }

if (xy == 'L') { return 50; }

if (xy == 'C') { return 100; }

if (xy == 'D') { return 500; }

if (xy == 'M') { return 1000; }

return -1;

}

// Convert to numbers , taking Variable named input as input

int Converted(string &input)

{

// Declare a variable to store the calculated output

int calc;

// Set to 0

calc = 0;

// Iterate through input from 0 to the last character

for (int i=0; i<input.length(); i++)

{

int check1 = value(input[i]);

if (i+1 < input.length())

{

int check12= value(input[i+1]);

// Comparing both values

if (check1>= check2)

{

calc+ =check1;

}

else

{

calc+ =check2 - check1;

i++;

}

}

else

{

calc+ =check1;

}

}

return calc;

}

// Main method starts here

int main()

{

// String input declaration

string inp;

cout<"Enter any valid Roman numeral";

cout << "Result is "

<< Converted(inp);

return 0;

}

3 0
3 years ago
This logo bby im sorry huhu​
Stels [109]

Answer:

I believe this was for someone else online, Unfortunately that's a little weird to be dating here ya know, Never know if there is someone really old or young you could be dating.

7 0
2 years ago
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