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MAVERICK [17]
3 years ago
5

Three letters are chosen at random from the letters P, A, N, S, O, L. What is the size of the sample space of this experiment? A

ssume that the order of the letters matters. That is, PAN is different from APN
Mathematics
2 answers:
AVprozaik [17]3 years ago
3 0
You need to find the number of permutations of the 6 different letters, taken 3 at a time.
6P3=\frac{6!}{(6-3)!}=\frac{6\times5\times4\times3\times2\times1}{3\times2\times1}=120
Therefore the sample space is 120 possible outcomes.
Allisa [31]3 years ago
3 0
If all the letters are different,
Using combinations:

<span>6C3 =6! /3!* (6-3)!
</span>Simplifying,
6C3 = 6x5x4 /1x2x3
       = 120/6
        = 20 ways 
Hence,
The size of the sample space will be 20.
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<h3>Equation</h3>

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