Three letters are chosen at random from the letters P, A, N, S, O, L. What is the size of the sample space of this experiment? A
ssume that the order of the letters matters. That is, PAN is different from APN
2 answers:
You need to find the number of permutations of the 6 different letters, taken 3 at a time.
Therefore the sample space is 120 possible outcomes.
If all the letters are different,
Using combinations:
<span>6C3 =6! /3!* (6-3)!
</span>Simplifying,
6C3 = 6x5x4 /1x2x3
= 120/6
= 20 ways
Hence,
The size of the sample space will be 20.
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