All categories

3 years ago

TIMED PLEASE HELP EDGE 2021

Mathematics

1 answer:

Inessa [10]3 years ago

4 0

The answer is A or b u choose the answer

You might be interested in

A number is no more than negative 5 or is between 0 and is 6

Sonbull [250]

Next time please include a picture so I can answer the question , if you are able to edit the question, please do and comment to notify me you have! then I will either my answer to your needs! thank you ~~♡♡ chyna

8 0

3 years ago

Read 2 more answers

If you work for an hourly wage, your gross pay is a function of the number of hours that you work. What is the independent varia

ale4655 [162]

In this case, the independent variable is the number of hours you work, and the dependent variable is your gross pay.

Brainliest please

4 0

3 years ago

Read 2 more answers

HELP HELP HELP PLS

Oksi-84 [34.3K]

Answer:

21 is common denominator.

15 and 7 are the corresponding numberators.

Step-by-step explanation:

You multiply the 7 and 6, then apply to the fractions, and slowly reduce until you find a good match.

8 0

3 years ago

Read 2 more answers

mr.cullen needs 91 carpet squares. he has 49 carpet squares. if the squares are sold in boxes of 6, how many more boxes of carpe

dolphi86 [110]

He need 7 more carpet squares

6 0

3 years ago

Solve the equation for all real values of x.<br> cosxtanx - 2 cos x=-1

IceJOKER [234]

Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

<u>Step-by-step explanation:</u>

Here we have , $cosxtanx - 2 cos^2 x=-1$ . Let's solve :

⇒ $cosxtanx - 2 cos^2 x=-1$

⇒ $cosx(\frac{sinx}{cosx}) - 2 cos^2 x=-1$

⇒ $sinx = 2 cos^2 x-1$

⇒ $sinx = 2 (1-sin^2x)-1$

⇒ $sinx = 1-2sin^2x$

⇒ $2sin^2x+sinx-1=0$

By quadratic formula :

⇒ $sinx = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $sinx = \frac{-1 \pm \sqrt{1^2-4(2)(-1)} }{2(2)}$

⇒ $sinx = \frac{-1 \pm3}{4}$

⇒ $sinx = \frac{1}{2} , sinx =-1$

⇒ $sinx = sin\frac{\pi}{6} , sinx = sin\frac{3\pi}{2}$

⇒ $x=\frac{\pi}{6} , x=\frac{3\pi}{2}$

But at $x=\frac{3\pi}{2}$ we have equation undefined as $cos\frac{3\pi}{2}=0$ . Hence only solution is :

⇒ $x=\frac{\pi}{6}$

Since , $sin(\pi -x)=sinx$

⇒ $x=\pi -\frac{\pi}{6} = \frac{5\pi}{6}$

Now , General Solution is given by :

⇒ $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$

Therefore , Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

3 0

3 years ago