Answer:
○ 
Explanation:
Accourding to one of the circle equations,
the centre of the circle is represented by
Moreover, all negative symbols give you the OPPOCITE TERMS OF WHAT THEY <em>REALLY</em> ARE, so you must pay cloce attention to which term gets which symbol. Another thing you need to know is that the radius will ALWAYS be squared, so no matter how your equation comes about, make sure that the radius is squared. Now, in case you did not know how to define the radius, you can choose between either method:
Pythagorean Theorem

Sinse we are dealing with <em>length</em>, we only desire the NON-NEGATIVE root.
Distanse Equation
![\displaystyle \sqrt{[-x_1 + x_2]^2 + [-y_1 + y_2]^2} = d \\ \\ \sqrt{[-7 + 4]^2 + [-2 - 2]^2} = r \hookrightarrow \sqrt{[-3]^2 + [-4]^2} = r \hookrightarrow \sqrt{9 + 16} = r; \sqrt{25} = r \\ \\ \boxed{5 = r}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Csqrt%7B%5B-x_1%20%2B%20x_2%5D%5E2%20%2B%20%5B-y_1%20%2B%20y_2%5D%5E2%7D%20%3D%20d%20%5C%5C%20%5C%5C%20%5Csqrt%7B%5B-7%20%2B%204%5D%5E2%20%2B%20%5B-2%20-%202%5D%5E2%7D%20%3D%20r%20%5Chookrightarrow%20%5Csqrt%7B%5B-3%5D%5E2%20%2B%20%5B-4%5D%5E2%7D%20%3D%20r%20%5Chookrightarrow%20%5Csqrt%7B9%20%2B%2016%7D%20%3D%20r%3B%20%5Csqrt%7B25%7D%20%3D%20r%20%5C%5C%20%5C%5C%20%5Cboxed%7B5%20%3D%20r%7D)
Sinse we are dealing with <em>distanse</em>, we only desire the NON-NEGATIVE root.
I am joyous to assist you at any time.
Answer:
(21 and 54): 3
(55 and 90): 5
(16 and 30): 2
(42 and 91): 7
(66 and 121): 11
Step-by-step explanation:
8 would be more times than it's of pyramid b then A
For this case we have that the point-slope equation of a line is given by:

Where:
m: It is the slope of the line
It is a point through which the line passes
In this case we have to:

Substituting in the equation we have:

Answer:

We just need to replace the value of the slope
Answer:
Step-by-step explanation:
I figured this out with calculus since it's easier that way. The position function for the ball is
. The first derivative of position is velocity, so we need to find the first derivative of the position function which is
v(t) = -32t + 64
Now, where the ball is at its highest point is where the velocity is equal to 0, so setting the velocity function equal to 0 allows us to determine how many seconds it takes to get to that max height.
0 = -32t + 64 and
-64 = -32t so
t = 2 seconds. It takes 2 seconds to get to its max height. In order to determine that max height, we sub 2 in for t in the position function:
and
s(2) = 66 feet. The max height of the ball is 66 feet.