By how much does a a^3-2a exceed a^2 + a -6
1 answer:
Answer:
a³ - a² - 3a+ 6
Step-by-step explanation:
we are asked by how much does (a³-2a) exceed (a²+a-6)
in other words, we are being asked to find the difference between the 2 terms above.
Mathematically we are asked to find:
(a³-2a) - (a²+a-6) (expand parentheses by distribution property)
=(a³-2a - a²- a + 6)
= a³ - a² - 3a+ 6 (answer)
You might be interested in
Answer:
7/4
Step-by-step explanation:
1 3/4=1 x 4=4 + 3=7/4
Answer:
Yes
Step-by-step explanation:
Switch x for 6:
(6)-8=-2
Subtract 6 from 8:
-2=-2
-2 does equal -2 so 6 is a solution.
Answer:
x = 7
Step-by-step explanation:
3x - 17 = 25 - 3x
Get the x's on one side and the integers on the other
3x + 3x = 25 + 17
6x = 42
x = 7
Answer:
Yes
Step-by-step explanation:
The equation y = 9x does intersect at the point (0,0) so therefore it is a solution.
Im not sure how to put the sign here but x= long division sign 3+5, negative sign in front of long division sign 3+5