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andrew11 [14]
3 years ago
7

A sports team is building a new stadium on a rectangular lot of land. If the lot measures 7x by 7x and the sports field will be

5x by 5x, how much of the lot will be left over to build bleachers on?
A. 4x²
B. 24x²
C. 74x²
D. 49x² - 25x²
Mathematics
2 answers:
padilas [110]3 years ago
7 0
7x*7x=49x^2, so the lot measures 49x^2.

The sports field, however, measures 5x*5x=25x^2.

The difference between these is 49x^2-25x^2=24x^2, or B.
Drupady [299]3 years ago
7 0
(7x · 7x) - (5x · 5x)
49x² - 25x²
24x²

It is equal to B.

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Scrat [10]

Answer:

-\frac{15}{2}

Step-by-step explanation:

\mathrm{Subtract\:}135\mathrm{\:from\:both\:sides}

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\mathrm{Simplify}

4x^2+12x-135=0

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What is an equation to show the relationship between 7 meters and 0.007 kilometers
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Answer:

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or

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4 years ago
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Vance weighs 250 pounds and is losing 5 pounds each month. Phillip weighs 200 pounds
Lelu [443]

Answer:

250-5m=200+4m ; 5.56 months

Step-by-step explanation:

<u>Let's start this question by writing two expressions that depict the situation.</u>

Vance: 250-5m

This simply means that Vance currently weighs 250 pounds, and every month he is losing 5 pounds. (m=number of months)

Phillip: 200+4m

This is essentially the same thing. Phillips starting weight is 200, but here we use an addition sign because he is gaining 4 pounds every month as opposed to losing it.

To find the number of months it'll take for them to weigh the same, we just need to equate the values and solve for m.

<u>Our equation would then be:</u>

250-5m=200+4m

Let's solve the equation by bringing the variables to one side and the numbers to the other.

250-5m=200+4m

Subtract 4m from both sides

250-5m-4m=200+4m-4m

250-9m=200

Subtract 250 from both sides

250-250-9m=200-250

-9m=-50

Divide both sides by -9

m=5.556

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3 0
2 years ago
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z=(222-218)/14≈0.29

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The formula s = StartRoot StartFraction S A Over 6 EndFraction EndRoot gives the length of the side, s, of a cube with a surface
never [62]

Answer:

2\sqrt{2}\ ft\ longer

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A=6s^2

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3 years ago
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