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Kamila [148]
3 years ago
6

The temperature at 7pm was 45 degrees Fahrenheit. From 7pm to 11pm the temperature decreased 5 degrees each hour. Which equation

can be used to find t, the temperature at 11pm?
t = 45 - 5(11-7)
t = 45 - 5(11+7)
t = 45 / 5(11-7)
t = 45 + 5(11-7)
Mathematics
2 answers:
Svetllana [295]3 years ago
7 0

t = 45 - 5(11-7)

Hope that helps:)

matrenka [14]3 years ago
4 0

Answer:

t = 45 - 5(11-7)

Step-by-step explanation:

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. During the Grinch's engine test, if the path traveled is represented by the
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Step-by-step explanation:

For this exercise it is important to remember the multiplication of signs:

(+)(+)=+\\(-)(-)=+\\(-)(+)=-\\(+)(-)=-

You have the following function provided in the exercise, which represents the path traveled:

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In order to find the value of f(-2) you can follow these steps:

1. You need to substitute x=-2 into the function, then:

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2. Finally you must evaluate. Then you get:

f(-2) =-8+ 2\\\\f(-2)=-6

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Martin drives to work at a speed of 45 miles per hour. It takes him about 2 hours and 15 minutes to get to work. If gas costs $2
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Step-by-step explanation:

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nekit [7.7K]

Answer:

The three zeros of the original function f(x) are {-1/2, -3, -5}.

Step-by-step explanation:

"Synthetic division" is the perfect tool for approaching this problem.    Long div. would also "work."

Use -5 as the first divisor in synthetic division:

      ------------------------

-5    2     17    38    15

              -10  -35   -15

       --------------------------

         2      7     3     0

Note that there's no remainder here.  That tells us that -5 is indeed a zero of the given function.  We can apply synthetic div. again to the remaining three coefficients, as follows:

     -------------

-3    2     7    3

             -6   -3

     -----------------

        2     1     0

Note that the '3' in    2   7   3 tells me that -3, 3, -1 or 1 may be an additional zero.  As luck would have it, using -3 as a divisor (see above) results in no remainder, confirming that -3 is the second zero of the original function.

That leaves the coefficients 2   1.  This corresponds to 2x + 1 = 0, which is easily solved for x:

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Thus, the three zeros of the original function f(x) are {-1/2, -3, -5}.

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