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Mathematics

1 answer:

Ket [755]3 years ago

5 0

Answer:

x=0

Step-by-step explanation:

3*9+x=27-x [9^1=9]

27+x=27-x

27-27= x+x

2x=0

x=0

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The denominator of a fraction is two more than the numerator. If both numerator and denominator are decreased by six, the simpli

ira [324]

Answer:

$\dfrac{40}{42}$

Step-by-step explanation:

Let the numerator of the fraction=x

Since the denominator of a fraction is two more than the numerator.

Denominator=x+2

The fraction is therefore:

$\dfrac{x}{x+2}$

If both numerator and denominator are decreased by six, the fraction becomes:

$\dfrac{x-6}{x+2-6}$

The simplified result is $\dfrac{17}{18}$

Therefore:

$\dfrac{x-6}{x+2-6}=\dfrac{17}{18}\\$Next, we solve for x\\Cross multiply\\18(x-6)=17(x+2-6)\\18(x-6)=17(x-4)\\Expand the bracket\\18x-108=17x-68\\Collect like terms\\18x-17x=-68+108\\x=40$

Substituting x=40 into the initial fraction

$\dfrac{x}{x+2}=\dfrac{40}{40+2}=\dfrac{40}{42}$

Therefore, the original fraction is $\dfrac{40}{42}$

4 0

3 years ago

Is a function always a relation

ziro4ka [17]

Answer:

No, to be a function a relation must fulfill two requirements: existence and unicity.

Step-by-step explanation:

Existence is a condition that establish that every element of te domain set must be related with some element in the range. Example: if the domain of the function is formed by the elements (1,2,3), and the range is formed by the elements (10,11), the condition is not respected if the element "3" for example, is not linked with 10 or 11 (the two elements of the range set).
Unicity is a condition that establish that each element of the domain of a relation must be related with <u>only one</u> element of the range. Following the previous example, if the element "1" of the domain can be linked to both the elements of the range (10,11), the relation is not a function.