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Leto [7]
3 years ago
11

3 2/3+2.3 repeating

Mathematics
2 answers:
Dvinal [7]3 years ago
8 0

Answer:

6.

Step-by-step explanation:

2.3 repeating = 2 1/3

So 3 2/3 + 2 1/3

= 5 + 1

= 6.

Viefleur [7K]3 years ago
4 0

Answer: 6

Step-by-step explanation:

3\frac{2}{3}+2.3^-

Let's begin by converting the repeating decimal to a fraction and then to a mixed number.

Take the number:

2.3^-

Let x (our result) be equal to that number.

x=2.3^-

Multiply by 1 followed by as many zeros as repeating decimals; in this case 1. Therefore, 10.

10x=2.3^-*10

This basically moves the decimal point one number to the right and since we have infinite 3's, we simply move 1 three and add another.

10x=23.3^-

Subtract this and the original equation (x=2.3^-)

10x=23.3^-\\-x=2.3^-

-----------------

10 - 1 = 9 and we have the same infinite repeating number 3, therefore they cancel out, leaving 23-2 = 21

9x=21

Divide by 9

x=\frac{21}{9}

Simplify by 3.

21/3=7

9/3=3

x=\frac{7}{3}

Now, convert to a mixed number. To do this, divide.

7/3=2

6

-------

1

The 2 is the whole number, 1 is the numerator and 3 the denominator.

2\frac{1}{3}

------------------------------------------------------------------------------------------------

Now we can solve this;

3\frac{2}{3}+2\frac{1}{3}

Add the whole numbers and the fractions separately.

(3+2)+(\frac{2}{3}+\frac{1}{3})

5\frac{3}{3}

3 and 3 can be simplied.

3/3=1

3/3=1

5\frac{1}{1}

The result is 1, add this to the 5.

5+1=6

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