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avanturin [10]
3 years ago
11

What is the square root of 890?

Mathematics
2 answers:
EleoNora [17]3 years ago
6 0

Answer: 29.8328677804


Step-by-step explanation:


Ierofanga [76]3 years ago
4 0

The square root of 890 is 29.8328677804

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Worth 10 points please help me ASAP!
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(-1,-1)

Step-by-step explanation:

If you multiply the x and y points of A, (-3,-3), by 1/3 then you find: (-1,-1).

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Jamie and Hudson took a road trip to the beach. Their total distance traveled after getting on the highway can be found using th
lukranit [14]

The total distance is an illustration of a linear function.

<u>(1) Why the relationship is a function</u>

The relationship is a function because all input values of h, have exactly one corresponding output value of d

<u>(2) The function type</u>

The function is a discrete function, because the number of hours is an integer, and it cannot take decimal values (in this case)

<u>(3) The domain for a drive of 8 hours</u>

The domain is the set of time the girls drive.

So, the domain is: [0,8]

<u>(4) The range</u>

The function is given as:

d = 55h +10

When h = 0,

d = 55(0) +10 = 10

When h = 8,

d = 55(8) +10 = 450

So, the range is: [10,450]

<u>(5) The graph</u>

See attachment

<u>(6) The slope</u>

A linear function is represented as:

y = mx + c

Where:

m represents the slope.

So, by comparison:

Slope = 55

The slope in this case represents the distance travelled per hour

<u>(7) The y-intercept</u>

In (6) above, c represents the y-intercept.

So, by comparison:

c = 10

The y-intercept in this case represents the initial distance

Read more about linear functions at

brainly.com/question/15602982

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2 years ago
Simplify the expression 4x^3/28x^4
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1/7x

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2 years ago
The ideal width of a safety belt strap for a certain automobile is 6 cm. The actual width can vary by at most 0.45 cm. Write an
OlgaM077 [116]

Answer:

|x-6|\le 0.45

x\in [5.55,6.45]

Step-by-step explanation:

<u>Absolute Value Inequality</u>

Assume the actual width of a safety belt strap for a certain automobile is x. We know the ideal width of the strap is 6 cm. This means the variation from the ideal width is x-6.

Note if x is less than 6, then the variation is negative. We usually don't care about the sign of the variation, just the number. That is why we need to use the absolute value function.

The variation (unsigned) from the ideal width is:

|x-6|

The question requires that the variation is at most 0.45 cm. That poses the inequality:

|x-6|\le 0.45

That is the range of acceptable widths. Let's now solve the inequality.

To solve an inequality for an absolute value less than a positive number N, we write:

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This is a double inequality than can be easily solved by adding 6 to all the sides.

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Operating:

5.55\le x \le 6.45

That is the solution in inequality form. Expressing in interval form:

\boxed{x\in [5.55,6.45]}

3 0
3 years ago
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