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2 years ago

PLS HELP RN $4000 student loan. 10% compound interest annually. Total loan amount by 4 years?

Mathematics

1 answer:

ddd [48]2 years ago

3 0

Answer:

$2,400

Step-by-step explanation:

We get 10% of 4,000 by dividing 4,000 by 10.

4,000 ÷ 10 = 400

To get the amount that 4,000 is subtracted by we multiply 400 by 4.

400 × 4 = 1,600

To get the answer we subtract 4,000 by 1,600.

4,000 - 1,600 = 2,400

Hope I helped!

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Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).

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The Bernoulli distribution is a distribution whose random variable can only take 0 or 1

The value of E(x2) is p
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<h3>How to compute E(x2)</h3>

The distribution is given as:

p(0) = 1 - p

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The expected value of x2, E(x2) is calculated as:

$E(x^2) = \sum x^2 * P(x)$

So, we have:

$E(x^2) = 0^2 * (1- p) + 1^2 * p$

Evaluate the exponents

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Multiply

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Add

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<h3>How to compute V(x)</h3>

This is calculated as:

$V(x) = E(x^2) - (E(x))^2$

Start by calculating E(x) using:

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So, we have:

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Recall that:

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So, we have:

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$V(x) = p(1 - p)$

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

$E(x^{79}) = \sum x^{79} * P(x)$

So, we have:

$E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p$

Evaluate the exponents

$E(x^{79}) = 0 * (1- p) + 1 * p$

Multiply

$E(x^{79}) = 0 + p$

Add

$E(x^{79}) = p$

Hence, the value of E(x79) is p

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brainly.com/question/15246027

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