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laila [671]
3 years ago
6

Daisy is making solid spikes for her Halloween costume. The spikes are shaped like right circular cones with base radius of 222

inches and height of 666 inches. If Daisy has 360360360 cubic inches of material for making the spikes, what is the maximum number of spikes she can make? (Round your answer to the nearest whole number.)
Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
7 0
Please answer please please thank you
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Two storage sheds ye to have to same area. One is square and one is rectangular. The rectangular shed is 2 meters wide and 8 met
natima [27]
8 x 2 = 16

Square root of 16 = 4

One side of the square is 4 meters.
5 0
2 years ago
Evaluate 2/3x for x = 3/4. Please show your work.<br> Thank you!!! :)
GenaCL600 [577]
X = 3/4
So substitute x for 3/4 in <span> 2/3x
(3/4) x (2/3)

Now solve
</span>(3/4) x (2/3) = 1/2 or 0.5

5 0
3 years ago
HELPPPPPPPPPPPPPPPPPPPPPPPPPP
ss7ja [257]

Answer:

Step-by-step explanation:

+(+) Two like signs become a positive sign 3+(+2) = 3 + 2 = 5

−(−) 6−(−3) = 6 + 3 = 9

+(−) Two unlike signs become a negative sign 7+(−2) = 7 − 2 = 5

−(+) 8−(+2) = 8 − 2 = 6

7 0
3 years ago
Find the derivative.
Aleksandr [31]

Answer:

Using either method, we obtain:  t^\frac{3}{8}

Step-by-step explanation:

a) By evaluating the integral:

 \frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du

The integral itself can be evaluated by writing the root and exponent of the variable u as:   \sqrt[8]{u^3} =u^{\frac{3}{8}

Then, an antiderivative of this is: \frac{8}{11} u^\frac{3+8}{8} =\frac{8}{11} u^\frac{11}{8}

which evaluated between the limits of integration gives:

\frac{8}{11} t^\frac{11}{8}-\frac{8}{11} 0^\frac{11}{8}=\frac{8}{11} t^\frac{11}{8}

and now the derivative of this expression with respect to "t" is:

\frac{d}{dt} (\frac{8}{11} t^\frac{11}{8})=\frac{8}{11}\,*\,\frac{11}{8}\,t^\frac{3}{8}=t^\frac{3}{8}

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:

"If f is continuous on [a,b] then

g(x)=\int\limits^x_a {f(t)} \, dt

is continuous on [a,b], differentiable on (a,b) and  g'(x)=f(x)

Since this this function u^{\frac{3}{8} is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:

\frac{d}{dt} \int\limits^t_0 {u^\frac{3}{8} } } \, du=t^\frac{3}{8}

5 0
3 years ago
A standard clock has a 1-cm hour hand and a 2-cm minute hand. At 12 pm, they are both pointing in the same direction and the dis
Levart [38]

Answer:

The distance between the hands is √(3)cm ≈ 1.73cm.

Step-by-step explanation:

In a standard clock, the angle between every number is 30°, therefore the angle between 12 and 2 will be 30° x 2 = 60°.

Looking at the diagram, to find c we can make use of our cosine formula

c² = a² + b² –2abCos(C°)

a = 2, b = 1 and C° = 60°

Therefore we have:

c² = 2² + 1² –2 x 2 x 1 x cos(60°) =

c² = 4 + 1 – 4 x 0.5 =

c² = 5 – 2 =

c² = 3

c = √(3) ≈ 1.73

Therefore, the distance between the hands is √(3)cm ≈ 1.73cm.

8 0
2 years ago
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