Write the equation for the circle with center at (6,0) and radius of 6.
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Answer:
B
Step-by-step explanation:
Since the triangle is right use Pythagoras' identity to solve for BC
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
BC² = AB² + AC² ← substitute values
BC² = 18² + 80² = 324 + 6400 = 6724 ( take the square root of both sides )
BC = = 82 → B