Write the equation for the circle with center at (6,0) and radius of 6.

1 answer:

8 0

------------------------------------------------------------------------------------
General Equation of a circle with centre (a, b) and radius r
------------------------------------------------------------------------------------
(x − a)² + (y − b)² = r²

------------------------------------------------------------------------------------
Substitute (6,0) and r = 6
------------------------------------------------------------------------------------
(x - 6)² + (y - 0)² = 6²
(x - 6)² + y² = 36

------------------------------------------------------------------------------------
Answer: (x - 6)² + y² = 36 (Answer A)
------------------------------------------------------------------------------------

You might be interested in

A fourth degree polynomial with real coefficients can have -4, 8i,+4i, and as its zeros. True or false? Justify your answer.

liraira [26]

You didn't give the fourth zero, but the answer is still false. If you have a root or an imaginary number as a zero, then its conjugate is also a zero. So if 8i is a zero, then -8i must also be a zero, and if 4i is a zero, then -4i must be a zero, with those zeros and -4, the number of zeroes exceeds the number of zeroes that a fourth degree polynomial can have.

4 0

3 years ago

Write the equation of a line passing through -1,4 and perpendicular to x+2y=11

Sophie [7]

Y=2x+6
gradient is found from the formula,
$\frac{ - 1}{ - \frac{1}{2} } = 2$
y intercept is found by subbing the values of (-1,4) into the equation y=2x+c

8 0

3 years ago

My mommy is being mean :(

GREYUIT [131]

Lol why do u think that?

6 0

2 years ago

Read 2 more answers

Which product is negative?

GREYUIT [131]

Answer: The Last One

Step-by-step explanation: The Last One Would Be A Product Of Negative