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Rasek [7]
3 years ago
6

Consider the game of rock-paper-scissors to be an experiment. In the long run, roommate A chooses rock 62% of the time, and room

mate B chooses rock 62% of the time; roommate A selects paper 16% of the time, and roommate B selects paper 23% of the time; roommate A chooses scissors 22% of the time, and roommate B chooses scissors 15% of the time. (These choices are made randomly and independently of each other.) The probabilities were assigned using ______.
Mathematics
1 answer:
tekilochka [14]3 years ago
7 0

Answer:

Relative frequency method

Step-by-step explanation:

Relative Frequency is a classical approach to probability. It is the ratio of the occurrence of a singular event to the total number of outcomes. This is a tool that is often used after data collection.

In relative frequency, a single part of the data can be compared to the total amount of data collected. This is cleearly observed in the given question.

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The price of 1 youth ticket is $ 22

<em><u>Solution:</u></em>

Let "y" be the price of 1 youth ticket

Let "a" be the price of 1 adult ticket

To find: price of 1 youth ticket

<em><u>Brianna's family spent $134 on 2 adult tickets and 3 youth tickets at an amusement park</u></em>

So we can frame a equation as:

2 adult tickets x price of 1 adult ticket + 3 youth tickets x price of 1 youth ticket = 134

2 \times a + 3 \times y = 134

2a + 3y = 134 ---- eqn 1

<em><u>Max's family spent $146 on 3 adults tickets and 2 youth tickets</u></em>

So we can frame a equation as:

3 adult tickets x price of 1 adult ticket + 2 youth tickets x price of 1 youth ticket = 146

3 \times a + 2 \times y = 146

3a + 2y = 146 ----- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "y"</u></em>

Multiply eqn 1 by 3

6a + 9y = 402 ---- eqn 3

Multiply eqn 2 by 2

6a + 4y = 292 ----- eqn 4

Subtract eqn 4 from eqn 3

6a + 9y = 402

6a + 4y = 292

( - ) -------------------

5y = 110

y = 22

Thus the price of 1 youth ticket is $ 22

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