Let A represent the speed of car A. Using your formula,
.. A*2 = D
.. (A +15)*1.5 = D . . . . . the same distance in a shorter time at a higher speed
Equating the two expressions for D, we get
.. 2A = 1.5(A +15)
.. 2A = 1.5A +22.5 . . . . . eliminate parentheses
.. 0.5A = 22.5 . . . . . . . . .subtract 1.5A
.. A = 22.5/0.5 = 45 . . . .divide by 0.5
Car B was 15 mph faster than this.
Car B traveled at 60 miles per hour.
Answer:
60%
Step-by-step explanation:
First, find the total number of sixth graders
To do this, add the number of girls and boys together
girls+boys
There are 60 girls and 90 boys
60+90
150
Now, find the percent of sixth graders that are boys
To do this, divide the number of boys by the total number of sixth graders
boys/total sixth graders (part/whole)
There are 90 boys, and 150 total sixth graders
90/150
0.6
Convert to a percent. Multiply by 100 or move the decimal place two spots to the right
0.6*100=60
0.6-->6.0-->60.
So, 60% are boys
I can answer but ur not being specific it what is the 6 for and what is the 2 for because there’s a space