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Rasek [7]
3 years ago
6

Consider the game of rock-paper-scissors to be an experiment. In the long run, roommate A chooses rock 62% of the time, and room

mate B chooses rock 62% of the time; roommate A selects paper 16% of the time, and roommate B selects paper 23% of the time; roommate A chooses scissors 22% of the time, and roommate B chooses scissors 15% of the time. (These choices are made randomly and independently of each other.) The probabilities were assigned using ______.
Mathematics
1 answer:
tekilochka [14]3 years ago
7 0

Answer:

Relative frequency method

Step-by-step explanation:

Relative Frequency is a classical approach to probability. It is the ratio of the occurrence of a singular event to the total number of outcomes. This is a tool that is often used after data collection.

In relative frequency, a single part of the data can be compared to the total amount of data collected. This is cleearly observed in the given question.

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A second-degree polynomial is a quadratic polynomial. O A. True O B. False​
Ilia_Sergeevich [38]

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2 years ago
Read 2 more answers
How many pairs of consecutive natural numbers have a product of less than 40000? I am in 5th grade. This is supposed to be easy
Ugo [173]

Answer:

There are 199 pairs of consecutive natural numbers whose product is less than 40000.

Step-by-step explanation:

We notice that such statement can be translated into this inequation:

n \cdot (n+1) < 40000

Now we solve this inequation to the highest value of n that satisfy the inequation:

n^{2}+n < 40000

n^{2}+n -40000

The Quadratic Formula shows that roots are:

n_{1,2} = \frac{-1\pm\sqrt{1^{2}-4\cdot (1)\cdot (-40000)}}{2\cdot (1)}

n_{1,2} = -\frac{1}{2}\pm \frac{1}{2} \cdot \sqrt{160001}

n_{1} = -\frac{1}{2}+\frac{1}{2}\cdot \sqrt{160001}

n_{1} \approx 199.501

n_{2} = -\frac{1}{2}-\frac{1}{2}\cdot \sqrt{160001}

n_{2} \approx -200.501

Only the first root is valid source to determine the highest possible value of n, which is n_{max} = 199. Each natural number represents an element itself and each pair represents an element as a function of the lowest consecutive natural number. Hence, there are 199 pairs of consecutive natural numbers whose product is less than 40000.

6 0
2 years ago
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