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2 years ago

What is the square root 6n carried to the power of 2/3 in radical form

Mathematics

1 answer:

BaLLatris [955]2 years ago

7 0

Answer: $\sqrt[3]{6n}$

Step-by-step explanation:

We have the following expression:

$(\sqrt{6n})^{\frac{2}{3}}$

Which can be written as follows:

$((6n)^{\frac{1}{2}})^{\frac{2}{3}}$

Multiplying the exponents:

$(6n)^{\frac{1}{3}}$

Writing in radical form we finally have the result:

$\sqrt[3]{6n}$

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