Yeah sure! Just make sure to post them haha :)
1 kilometer=1000 meters so the 8 kilometers he ran would be 8000 meters then theres the 500 he sprinted. he climbed bleachers for 1.5 kilometers which would equal 1500 meters so 8000+500+1500=10,000. He traveled 10,000 kilometers.
The ratio of the volumes is equal to the scale factor cubed.
![\frac{V_1}{V_2}=k^3 \\ \\ \frac{320 \ cm^3}{1080 \ cm^3}=k^3 \\ \frac{8}{27}=k^3 \\ k=\sqrt[3]{\frac{8}{27}} \\ \boxed{k=\frac{2}{3}} \Leftarrow \hbox{answer B}](https://tex.z-dn.net/?f=%5Cfrac%7BV_1%7D%7BV_2%7D%3Dk%5E3%20%5C%5C%20%5C%5C%0A%5Cfrac%7B320%20%5C%20cm%5E3%7D%7B1080%20%5C%20cm%5E3%7D%3Dk%5E3%20%5C%5C%0A%5Cfrac%7B8%7D%7B27%7D%3Dk%5E3%20%5C%5C%0Ak%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B8%7D%7B27%7D%7D%20%5C%5C%0A%5Cboxed%7Bk%3D%5Cfrac%7B2%7D%7B3%7D%7D%20%5CLeftarrow%20%5Chbox%7Banswer%20B%7D)
Answer:
90
Step-by-step explanation:
6x4^2+(-2)x3=
6x16-2x3=
96-6=
90
Answer:
3y= -2x-6
Step-by-step explanation:
The two points on the line are (-3,0) and (0,-2)
so you first get the gradient;
gradient= <u>change in y</u>
change in x
= <u>-2-0</u>
0-(-3)
=<u> -2</u>
3
so the answer above is the gradient
then pick one point that you used to get the gradient with, so as for me I'll pick (-3,0) and then a general point which is always (x, y)
since you have the gradient you can easily get the equation by doing this
<u>y-0</u><u>. </u><u> </u> = <u>-2</u>
x-(-3). 3
then crossmultiply to get the equation of the line
3y= -2(x+3)
3y= -2x-6
