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denis-greek [22]
4 years ago
3

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the gr

ound. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?
1s

2s

3s

4s
Mathematics
2 answers:
Nina [5.8K]4 years ago
7 0
H(t) = -16t^2 + 27x + 10
At the point the object hits the ground, h(x) = 0
-16x^2 + 27x + 10 = 0
16x^2 - 27x - 10 = 0
x = (27 + sqrt(27^2 - 4 x 16 x -10)) / (2 x 16) = (27 + sqrt(729 + 640)) / 32 = (27 + 37) / 32 = 64 / 32 = 2

Therefore, the object will hit the ground after 2 seconds.
SCORPION-xisa [38]4 years ago
4 0

Answer:

The answer is actually 2s

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Answer:

A) Both events are not independent.

B) Both events are not mutually exclusive

C) 8.33%

D) 80%

Step-by-step explanation:

A) Both events are not independent. This is because, If B occurs it means that it is very likely that J will occur as well.

B) Both events are not mutually exclusive. This is because it is possible for both events J and B to occur at the same time.

C) we want to find the probability that Joe who is not a business student will receive the job offer.

This is;

P(J|Not B) = P(J & Not B)/P(Not B)

Now,

P(J & Not B) = P(J) – (P(B) × P(J | B))

25% of the students who attended received job offers. Thus; P(J) = 0.25

40% were from the College of Business. Thus;

P(B) = 0.4

Among the business students, 50% received job offers. Thus;

P(J|B) = 0.5

Thus;

P(J & Not B) = 0.25 - (0.4 × 0.5)

P(J & Not B) = 0.25 - 0.2

P(J & Not B) = 0.05

Since P(B) = 0.4

Then, P(Not B) = 1 - 0.4 = 0.6

Thus;

P(J|Not B) = 0.05/0.6

P(J|Not B) = 0.0833 = 8.33%

D) This probability is represented by;

P(B | J) = P(B & J)/P(J)

P(B & J) = (P(B) × P(J | B)) = (0.4 × 0.5) = 0.2

P(B | J) = 0.2/0.25

P(B | J) = 0.8 = 80%

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