Question

A ball is thrown into the air with a initial velocity of 25 meters per second.The function h(t)+-4.9t^2+25t+6 represents the height of the t in seconds. ball above the ground in meters,with respect to time.at h(3) then the height of the ball would be

Answer 1

Answer:

36.9 m

Step-by-step explanation:

h(t) = -4.9t² + 25t + 6

At t = 3:

h(3) = -4.9(3)² + 25(3) + 6

h(3) = -44.1 + 75 + 6

h(3) = 36.9

After 3 seconds, the ball will have a height of 36.9 meters.