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____ [38]
3 years ago
14

Adam has 12 bags of pumpkin seeds that each weigh 3/8. How many ounces of pumpkin seeds does he have in all? / What is the total

weight of all 12 bags?
Mathematics
2 answers:
balandron [24]3 years ago
4 0
Adam has 4 1/2 or 4.5 ounces of pumpkin seeds.
To find the answer you need to multiply 12 by 3/8 because the word each means multiplication
So 12*3/8=12/1*3/8 because to multiply whole numbers by fractions you first need to convert 12 into a fraction so 12 as a fraction is 12/1.Next you multiply across so you will end up having 36/8.Then you can reduce 36/8 and you will end up having 9/2.(you simplify by looking at which number could go into 36 and 8 and in this case it would be 4 then you have to divide 36 and 8 by 4).
Finally you convert 9/2 into a mixed number and you will end up with 4 1/2.(you convert an improper fraction into a mixed number by dividing the numerator by your denominator).
Natasha_Volkova [10]3 years ago
3 0
4.5 ounces.. 12x3/8=4.5
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The correct answer is C.
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14 POINTS for solving x in 14 Angle Relationships problems
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3 years ago
If someone flips switches on the selection in a completely random fashion, what is the probability that the system selected cont
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 Given that a display allows a customer to hook together any selection of components, one of each type. These are the types:
Receiver: Kenwood, Onkyo, Pioneer, Sony, Sherwood
CD player: Onkyo, Pioneer, Sony, Technics
Speakers: Boston, Infinity, Polk
Cassette: Onkyo, Sony, Teac, Technics:

Part (a):
In how many ways can one component of each type be selected?

The number of ways one type of receiver will be selected is given by 5C1 = 5
The number of ways one type of CD player will be selected is given by 4C1 = 4
The number of ways one type of speakers will be selected is given by 3C1 = 3
The number of ways one type of cassette will be selected is given by 4C1 = 4

Therefore, the number of ways one component of each type can be selected is given by 5 x 4 x 3 x 4 = 240 ways



Part (b):
In how many ways can components be selected if both the receiver and the compact disc player are to be Sony?

The number of ways of selecting a Sony receiver is 1
The number of ways of selecting a Sony CD player is 1
The number of ways one type of speakers will be selected is given by 3C1 = 3
The number of ways one type of cassette will be selected is given by 4C1 = 4

Therefore, the number of ways components can be selected if both the receiver and the compact disc player are to be Sony is given by 1 x 1 x 3 x 4 = 12



Part (c)
In how many ways can components be selected if none of them are Sony?

The number of ways one type of receiver that is not Sony will be selected is given by 4C1 = 4
The number of ways one type of CD player that is not Sony will be selected is given by 3C1 = 3
The number of ways one type of speakers that is not Sony will be selected is given by 3C1 = 3
The number of ways one type of cassette that is not Sony will be selected is given by 3C1 = 3

Therefore, the number of ways that components can be selected if none of them are Sony is given by 4 x 3 x 3 x 3 = 108



Part (d):
In how many ways can a selection be made if at least one Sony component is to be included?

The total number of ways of selecting one component of each type is 240
The number of ways that components can be selected if none of them are Sony is 108

Therefore, the number of ways of selecting at least one Sony component is given by 240 - 108 = 132



Part (e):
If someone flips switches on the selection in a completely random fashion, what is the probability that the system selected contains at least one Sony component?

The total number of ways of selecting one component of each type is 240
The number of ways of selecting at least one Sony component is 132

Therefore, the probability that a system selected at random contains at least one Sony component is given by 132 / 240 = 0.55



Part (f):
If someone flips switches on the selection in a completely random fashion, what is the probability that the system selected contains exactly one Sony component? (Round your answer to three decimal places.)

The number of ways of selecting only a Sony receiver is given by 1 x 3 x 3 x 3 = 27
The number of ways of selecting only a Sony CD player is given by 4 x 1 x 3 x 3 = 36
The number of ways of selecting only a Sony cassette is given by 4 x 3 x 3 x 1 = 36

Thus, the number of ways of selecting exactly one Sony component is given by 27 + 36 + 36 = 99

Therefore, the probability that a system selected at random contains exactly one Sony component is given by 99 / 240 = 0.413
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