Please consider the attached file.
We can see that triangle JKM is a right triangle, with right angle at M. Segment KM is 6 units and segment MJ is 3 units. We can also see that KJ is hypotenuse of right triangle.
We will use Pythagoras theorem to solve for KJ as:
Now we will take positive square root on both sides:
Therefore, the length of line segment KJ is 
and option D is the correct choice.
Angle 1 and 2 are vertical angles
Hope this helps :)
Answer:
A
Step-by-step explanation:
The triangles aren't similar.
The triangles share a side so we cant use anything involving SSS SAS.
The triangles has only known congruent angle so we cant use AA.
Given AP is 21 ,18,15,...
First term = 21
Common difference = 18-21 = -3
Let an = -81
We know that
an = a+(n-1)d
⇛21+(n-1)(-3) = -81
⇛ 21-3n+3 = -81
⇛24-3n = -81
⇛ 24+81 = 3n
⇛ 105= 3n
⇛ n = 105/3
⇛ n = 35
35th term of the AP is -81.
<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> Which term of a AP 5 , 13 , 21 ,... is 181?
brainly.com/question/2406241?referrer
Which term of the AP:3, 8, 13, 18,...,is 78?
brainly.com/question/15380012?referrer
Answer:
11847
Step-by-step explanation:
8900e ^0.026(11)
8900e^0.286
11846.7228518
answer 11847
