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3 years ago

Approximately how many times greater is

2 answers:

6 0

7.4 x 10^8= 740000000
2.5 x 10^7: 25000000

Answers If You Use The Other Numbers
x0.3= 7500000
x3= 75000000
x30= 750000000
x300= 7500000000

Answer: Not Possible

If You Did 7.5 x 10^8 it will make more sense but you didn’t so the answer is unspecified.

katovenus [111]3 years ago

3 0

Answer:

Step-by-step explanation:

To compare the numbers, divide the first number by the second number.

(7.4 x 10^8)/(2.5 x 10^7) = (74 x 10^7)/(2.5 x 10^7) = 74/2.5 = 29.6

Answer: 30

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The base of an aquarium with given volume V is made of slate and the sides are made of glass. If the slate costs seven times as

lubasha [3.4K]

Answer:

$l = \sqrt[3]{\frac{2V}{7}}$ $b = \sqrt[3]{\frac{2V}{7}}$ $h = \sqrt[3]{\frac{49V}{4}}$

Step-by-step explanation:

Represent the volume of the box with V and the dimensions with l, b and h.

The volume (V) is:

$V = l * b * h$

Make h the subject of the formula

$h = \frac{V}{lb}$

The surface area (S) of the aquarium is:

$S = lb + 2(lh + bh)$

Where lb represents the area of the base (i.e. slate):

The cost (C) of the surface area is:

$C = 7 * lb + 1 * 2(lh + bh)$

$C = 7lb + 2(lh + bh)$

$C = 7lb + 2h(l + b)$

Substitute $\frac{V}{lb}$ for h in the above equation

$C = 7lb + 2*\frac{V}{lb}(l + b)$

$C = 7lb + \frac{2V}{lb}(l + b)$

$C = 7lb + \frac{2V}{b} + \frac{2V}{l}$

Differentiate with respect to l and with respect to b

$C_l=7b - \frac{2V}{l^2}$ $=0$

$C_b=7l - \frac{2V}{b^2}$ $=0$

To solve for b and l, we equate both equations and set l to b (to minimize the cost)

$7b - \frac{2V}{l^2}=7l - \frac{2V}{b^2}$

$7l - \frac{2V}{l^2}=7b - \frac{2V}{b^2}$

By comparison:

$l =b$

$C_l=7b - \frac{2V}{l^2}$ $=0$ becomes

$7l - \frac{2V}{l^2}=0$

$7l = \frac{2V}{l^2}$

Cross Multiply

$7l^3 = 2V$

Solve for l

$l^3 = \frac{2V}{7}$

$l = \sqrt[3]{\frac{2V}{7}}$

Recall that: $l =b$

$b = \sqrt[3]{\frac{2V}{7}}$

Also recall that:

$h = \frac{V}{lb}$

$h = \frac{V}{\sqrt[3]{\frac{2V}{7}}*\sqrt[3]{\frac{2V}{7}}}$

$h = \frac{V}{\sqrt[3]{\frac{4V^2}{49}}}$

Apply law of indices

$h = \sqrt[3]{\frac{49V^3}{4V^2}}$

$h = \sqrt[3]{\frac{49V}{4}}$

The dimension that minimizes the cost of material of the aquarium is:

$l = \sqrt[3]{\frac{2V}{7}}$ $b = \sqrt[3]{\frac{2V}{7}}$ $h = \sqrt[3]{\frac{49V}{4}}$

8 0

3 years ago

Please help, i'll give brainliest

qaws [65]

Answer:

Step-by-step explanation:

You want ...

4x +24 = 8x

24 = 4x . . . . . . . . subtract 4x

6 = x . . . . . . . . . . .divide by 4

When x=6, the slats are parallel.

3 0

3 years ago

1 - 3/10 - 1/10 please help

777dan777 [17]

Answer:

0.2 in decimal form and 1/5 in fraction form

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the slope and y-intercept of the equation 6x - 1 = 3y - 10?*

Ad libitum [116K]

Answer:

m = 2, b = 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and b the y- intercept )

Given

6x - 1 = 3y - 10 ( add 10 to both sides )

6x + 9 = 3y ( divide all terms by 3 )

2x + 3 = y , that is

y = 2x + 3 ← in slope- intercept form

with slope m = 2 and y- intercept b = 3

6 0

3 years ago

Simon walks a total of 45.55 miles in March and 35.7 miles in April.

stich3 [128]

Answer:

81.25

Step-by-step explanation:

45.55 + 35.7

5 0

3 years ago