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Vsevolod [243]
3 years ago
5

What is the vertex of the quadratic function y=3x^2-12x+8

Mathematics
2 answers:
aksik [14]3 years ago
5 0
The answer is (2,-4)
pashok25 [27]3 years ago
4 0

Answer:

the vertex  of 3x^2-12+8 is (2,-4)

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There is 0.162 liter of water in a 1-liter bottle. How much more water should be put in the bottle so it contains exactly 1 lite
Dmitry [639]

Answer: 0.838 is the answer to this problem

Because 1.000 - .162= 0.838

3 0
3 years ago
Jada solved the equation Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction for x using the step
GalinKa [24]

Answer:

Jada should have multiplied both sides of the equation by 108.

Step-by-step explanation:

The question is incomplete. Find the complete question in the comment section.

Given the equation -4/9 = x/108, in order to determine Jada's error, we need to solve in our own way as shown:

Step 1: Multiply both sides of the equation by -9/4 as shown:

-4/9 × -9/4 = x/108 × -9/4

-36/-36 = -9x/432

1 = -9x/432

1 = -x/48

Cross multiplying

48 = -x

x = -48

It can also be solved like this:

Given -4/9 = x/108

Multiply both sides by 108 to have:

-4/9 * 108 = x/108 * 108

-4/9 * 108 = 108x/108

-432/9 = x

x = -48

Jada should have simply follow the second calculation by multiplying both sides of the equation by 108 as shown.

7 0
3 years ago
PLEASE HELP !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Bond [772]

Answer:

R = \frac {3ST}{2S + T}

Step-by-step explanation:

Given the equation;

\frac {3}{R} - \frac {1}{S} = \frac {2}{T}

Rearranging the equation, we have;

\frac {3}{R} = \frac {2}{T} + \frac {1}{S}

Lowest common multiple (LCM) of S and T is ST.

\frac {3}{R} = \frac {2S + T}{ST}

Cross-multiplying, we have;

3ST = R(2S + T)

Making R, the subject of formula;

R = \frac {3ST}{2S + T}

8 0
3 years ago
Which of the following is a coterminal angle of 138°? A.) 438° B.)-136° C.) -582° D.) 228°
GaryK [48]

Answer:  I think the correct answer is D.

8 0
3 years ago
Read 2 more answers
Change to vertex form<br> 2x²16x+33
loris [4]

y=2x^2+16x+33\\\\y=2x^2+16x+32+1\\\\y=2(x^2+8x+16)+1\\\\y=2(x+4)^2+1\\\\or\\\\y=2x^2-16x+33\\\\y=2x^2-16x+32+1\\\\y=2(x^2-8x+16)+1\\\\y=2(x-4)^2+1

6 0
3 years ago
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