Answer:
The width of the floor is 10 ft.
Step-by-step explanation:
First, you have to form expressions of width and length in terms of w. With the given information :
width = w ft
length = (w - 2) ft
Given that the area of rectange is A = length × width so you have to subtitute the expressions and value into the formula :
A = l × w
80 = (w - 2) × w
w(w - 2) = 80
w² - 2w = 80
w² - 2w - 80 = 0
(w + 8)(w - 10) = 0
w + 8 = 0
w = -8 (rejected)
w - 10 = 0
w = 10
(x + 8)(y + 3)
x*(y+3) + 8*(y + 3)
x*y + 3*x + 8*y + 3*8
xy + 3x + 8y + 24
So the correct product is = xy + 3x + 8y + 24, I guess the second expression.
I hope this helps.
Answer:
D) y= 4x - 1
Step-by-step explanation:
We are basically trying to see which of the equations provided are true on both sides of the equal sign when you plug in the x and y values.
Let's start!
Choice A:
plug in 0 for x and -1 for y
-1 = 4(0)
And you are left with...
-1 = 0
This equation is false! Therefore it does not match the function in the table
Choice B:
plug in the values again
-1 = 0 + 1
-1 = 1
False!
Choice C:
-1 = 0 + 5
-1 = 5
False!
Lastly...Choice D:
-1 = 4(0) -1
Multiply 4 and 0 which is 0, so you are left with...
-1 = -1
This equation is true!!
So your answer is D
Hope this helps :D
Answer:
Step-by-step explanation:
Set up an equation, where x is the number of gallons of 60% antifreeze solution.
Represent the percentages of antifreeze with decimal values.
0.6x + 0.3(80) = 0.5(x + 80)
Simplify and solve for x:
0.6x + 24 = 0.5x + 40
0.1x = 16
x = 160
So, you have to mix 160 gallons of a 60% antifreeze solution
Answer:
Step-by-step explanation:
We are given that:
Where <em>A</em> is in QI.
And we want to find sec(A).
Recall that cosecant is the ratio of the hypotenuse to the opposite side. So, find the adjacent side using the Pythagorean Theorem:
So, with respect to <em>A</em>, our adjacent side is 63, our opposite side is 16, and our hypotenuse is 65.
Since <em>A</em> is in QI, all of our trigonometric ratios will be positive.
Secant is the ratio of the hypotenuse to the adjacent. Hence:
