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umka21 [38]
3 years ago
8

The ages of three siblings combined is 27. The oldest is twice the age of the youngest. The middle child is 3 years older than t

he youngest. Write and solve an equation to find the ages of each sibling.
Please help!
Mathematics
1 answer:
Free_Kalibri [48]3 years ago
6 0
X+y+z=27
lets say
x<y<z

z=2x
y=3+x

sub

x+y+z=27
x+3+x+2x=27
4x+3=27
minus 3
4x=24
divide by 4
x=6

y=3+x
y=3+6
y=9

z=2x
y=2(6)
y=12


ages are

6,9,12

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If we defined a as the bottom side, and b as the lateral side, we have the area defined as:

A=A_r+A_c/2=a\cdot b+\dfrac{\pi r^2}{2}=ab+\dfrac{\pi}{2}\left (\dfrac{a}{2}\right)^2=ab+\dfrac{\pi a^2}{8}

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