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Sati [7]
3 years ago
15

4/6 in the lowest term helpppppppppp!!!!!!!

Mathematics
2 answers:
Agata [3.3K]3 years ago
3 0

2/3 would be the answer hope this helps.

Klio2033 [76]3 years ago
3 0
1) find the GCF (greatest common factor) of 4/6
2) the GCF is 2 so divide 4 and 6 by 2
3) the most simplified fraction is 2/3
message me for any questions!!
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4)Without a calculator, name the zeros and sketch the graph.<br> 56.) = -2x(x-4)^2(x+3)^2
Ilia_Sergeevich [38]

Answer:

0, 4, -3

Step-by-step explanation:

replace y with 0 and then fro the sketch I recommend you tomuse desmos good luck buddie

6 0
3 years ago
What is the range of this function?
Rzqust [24]

Greetings.

The range is the set of y-value.

The range starts from the minimum point to maximum point.

Our minimum point starts at 0 and maximum point starts less than infinity.

Therefore the range is 0<=y<+inf

However, we do not often write that, although it is right.

Therefore we write as y≥0

Thus, the answer is B choice.

5 0
2 years ago
Plot the image of point D under a dilation about point P with a scale factor of
Vikentia [17]
It’s at point d and point p
5 0
2 years ago
For this function:
galina1969 [7]

Answer:

C)

Minimum of t = -\infty

Maximum of t = +\infty

Minimum of h(t) = -\infty

Maximum of h(t) = +20

D)

D(-\infty,+\infty)

R(-\infty,+20]

Step-by-step explanation:

C)

Here in this problem, we are given the function, which is

h(t)=-5t^2+20

We observe immediately the following:

- The function has no limitations on the value of t - in fact, it contains no square roots, no logarithms, and no fractions; therefore, every value of x is acceptable in this function. This means that it has the variable t has no minimum or maximum values.

- On the other hand, h(t) cannot take any value. In fact, we notice that this is a quadratic function with the second-degree term with a negative coefficient: this means that it is a downward parabola. So, it has no downward limit (it goes to -\infty), but it has a maximum, which corresponds to the vertex of the parabola.

The x-coordinate of the parabola is given by

x_v = -\frac{b}{2a}=0

because the coefficient of the 1st-degree term, b, is zero. So, the y-coordinate of the vertex is

h(0)=-5\cdot 0^2+20 = 20

So, the maximum of h(t) is 20. Therefore we have:

Minimum of t = -\infty

Maximum of t = +\infty

Minimum of h(t) = -\infty

Maximum of h(t) = +20

D)

The domain of a function is defined as the set of values of the independent function x for which the function has a valid value.

Therefore in this case, the domain of h(t) is the set of all values allowed for t: so, from part C, we can say that the domain is

D(-\infty,+\infty)

So, all real values.

The range of a function instead is the set of all values of the dependent variables, y.

So in this case, the range of h(t) is the set of all values that h(t) can take.

From part C, we know therefore that the range is

R(-\infty,+20]

Where +20 has the ] instead of ) because it is also an allowed value.

5 0
3 years ago
What is the answer for 30c=170
Ainat [17]

Answer:

c = 5  2/3

Step-by-step explanation:

30c = 170

c = 5  2/3

3 0
3 years ago
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