Answer:
(-6,4)
Step-by-step explanation:
If this is the system of equations here is how:
solve for 1 vairuble in the first equation, and plug that it to the other.
90. Add the zero in front of the 9.
ummmm it could be third one i guesss
1. You con solve the quadratic equation x^2+20x+100=50<span> by following the proccedure below:
2. Pass the number 50 from the right member to the left member. Then you obtain:
x^2+20x+100-50=0
</span><span> x^2+20x+50=0
</span><span>
3. Then, you must apply the quadratic equation, which is:
x=(-b±√(b^2-4ac))/2a
</span><span>x^2+20x+50=0
</span><span>
a=1
b=20
c=50
4. Therefore, when you substitute the values into the quadratic equation and simplify ir, you obtain that the result is:
-10</span>±5√2 (It is the last option).
Answer:
24
Step-by-step explanation:
since c=4 and d=48, we can re-write this equation
48-6 x 4
48 - 24
24
