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2 years ago

Which expression is equivalent to (4p^-4 q)^-2/ 10pq^-3?

Mathematics

2 answers:

Anit [1.1K]2 years ago

4 0

Answer:

$\dfrac{p^{7} q}{160}$

Step-by-step explanation:

$\dfrac{(4p^-4 q)^-2}{10pq^-3} =$

$= \dfrac{4^{-2}p^{-4\times (-2)} q^{-2}}{10pq^-3}$

$= \dfrac{4^{-2}}{10}p^{8-1} q^{-2-(-3)}$

$= \dfrac{1}{4^2 \times 10}p^{7} q^{-2 + 3}$

$= \dfrac{1}{160}p^{7} q$

$= \dfrac{p^{7} q}{160}$

iogann1982 [59]2 years ago

3 0

Answer:

C on e2020/edge

Step-by-step explanation:

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Answer:

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1 year ago

What are the zeros of the polynomial function

solniwko [45]

Option B

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Solution:

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To find the zeros of polynomial function, set the function equal to zero and then solve for x.

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Taking "x" as common term, we get

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Let us solve $x^2 - 5x - 6 = 0$ to find other zeros

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Using the above formula,

$\text{ for } x^2 - 5x - 6 = 0 \text{ we have } a = 1 ; b = -5 ; c = -6$

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Substituting the values of a, b, c in above formula,

$x=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2(1)}\\\\x=\frac{5 \pm \sqrt{25+24}}{2}=\frac{5 \pm \sqrt{49}}{2}\\\\x=\frac{5 \pm 7}{2}\\\\x=\frac{5+7}{2} \text{ or } x=\frac{5-7}{2}\\\\x=\frac{12}{2} \text{ or } x=\frac{-2}{2}\\\\x=6 \text{ or } x=-1$

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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

We take the denominator.

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