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Artemon [7]
2 years ago
8

Find the measures of the angles labeled in the figure on the right

Mathematics
1 answer:
vagabundo [1.1K]2 years ago
7 0

Answer:

Step-by-step explanation:

EFD = 90* (straight line = 180, and other angle is 90)

EHF = 180-52 = 128* (again straight line)

HFG = 90-32 = 58* (its a right angle (can tell by the square angle) = 90*)

G = 180 - 52 - 58 = 70* (angles in triangle = 180)

E = 180 - 32 - 128 = 20* (angles in triangle = 180)

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Please Help!
Lisa [10]
We know that

in the right triangle
sin x=opposite side angle x/hypotenuse
opposite side angle x=66 mm
hypotenuse=79 mm
so
sin x=66/79
x=arc sin (66/79)-------> x=56.66°-------> x=56.7°

the answer is
x=56.7°
7 0
3 years ago
123
ser-zykov [4K]

First, I'm going to separate factor the expression inside of the square root.

sqrt[ (2/18) * (x^5) ]

sqrt[ (1/9) * (x^5) ]

We can take the square root of 1/9 easily, because 1 and 9 are both perfect squares. The square root of 1/9 is 1/3.

Looking at the x^5, we can separate it into x^2 * x^2 * x^1. The square root of x^2 is x. So, we now also have an x^2 on the outside because there are two x^2s in our expanded form.

ANSWER: (x^2 * sqrt(x)) / 3

(Option 1)

Hope this helps!

4 0
2 years ago
carlos registro la altura de una planta cada una semana y se dio cuenta que esta crecio constantemente 3 cm durante las primeras
kogti [31]

Answer:

yo soy inteligente

Step-by-step explanation:

pero no me se la respuesta de la perunta

7 0
2 years ago
Using the quadratic formula, what is the solution to 2x^2-5x-6=0 ?
Alex17521 [72]
\bf \textit{quadratic formula}\\

\begin{array}{lcclll}
2x^2&-5x&-6&=0\\
\uparrow &\uparrow &\uparrow \\
a&b&c
\end{array}
\qquad \qquad 
x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}\\\\
-----------------------------\\\\
x=\cfrac{-(-5)\pm\sqrt{(-5)^2-4(2)(-6)}}{2(2)}\implies x=\cfrac{5\pm\sqrt{25+48}}{4}
\\\\\\
x=\cfrac{5\pm\sqrt{73}}{4}\implies x=
\begin{cases}
\cfrac{5+\sqrt{73}}{4}\\\\
\cfrac{5-\sqrt{73}}{4}
\end{cases}
4 0
3 years ago
One winter day, the temperature increased from a low -5 degrees F to a high of 40 degrees F.BY how many degrees did the temperat
sertanlavr [38]

Answer:

The temperature changed by 45˚

Step-by-step explanation:

Set up an algebraic equation

-5 + x = 40

Add 5 to both sides

x = 45

8 0
3 years ago
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