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2 years ago

14

SOMEONE PLEASE HELP ME ASAP PLEASE!!!!!

1 answer:

Liula [17]2 years ago

5 0

Answer:

T(x, y) = (x - 5, y - 6)

Step-by-step explanation:

The transformation T is a translation that creates an image P' of original point P by adding 5 to the x-coordinate and 6 to the y-coordinate of the original point P.

Now you want to transform point P' into point P, so you are undoing the first transformation. You need to do the opposite of what the transformation above does. You need to subtract 5 from the x-coordinate and subtract 6 from the y-coordinate.

Answer: T(x, y) = (x - 5, y - 6)

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Determine whether the sequence is arithmetic or geometric.

Elanso [62]

Sequence 1 is arithmetic because it is being subtracted by 16.

Sequence 2 is geometric because it is being divided by 2.

Arithmetic is when you're adding or subtracted and geometric is when you multiplying or dividing.

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3 years ago

Read 2 more answers

a car was valued at $41,000 in the year 2009 by 2013 the car value has depreciated to 19,000 if the car value continues to by th

lubasha [3.4K]

Answer:

$6,376.92

Step-by-step explanation:

-Let d be the rate of depreciation per year.

-Therefore, the value after n years can be expressed as:

$A=P(1-d)^n\\\\A=Value \ after \ n \ years\\P=Initial \ Value\\d=Rate \ of \ depreciation\\n=Time \ in \ years$

#We substitute for the years 2009-2013 to solve for d:

$A=P(1-d)^n\\\\19000=41000(1-d)^4\\\\0.475=(1-d)^4\\\\d=1-0.475^{0.25}\\\\d=0.1698$

#We then use the calculated depreciation rate above to solve for A after 10 yrs:

$A=P(1-d)^n\\\\=41000(1-0.1698)^{10}\\\\=\$6,376.92$

Hence, the value of the car after 10 yrs is $6,376.92

3 0

3 years ago

The longest side of an isosceles obtuse triangle measures 20 centimeters. The other two side lengths are congruent but unknown.

morpeh [17]

B.10 cm hopes this helps

7 0

3 years ago

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The center of an ellipse is (-9,3). one focus is (-7,3). The major axis is 24 units long. What is the equation of the ellipse in

CaHeK987 [17]

Answer:

$\frac{(x+9)^2}{144}+\frac{(y-3)^2}{140}=1$

Step-by-step explanation:

The standard equation of the ellipse is

$\frac{(x-\alpha)^2}{a^2}+\frac{(y-\beta)^2}{b^2}=1\;\cdots(i)$

where, $(\alpha, \beta)$ is the center and a,b are semi axes of the ellipse along x-axis and y-axis respectively.

Given that, $(\alpha, \beta)=(-9,3)$ and major axis, $2a=24$ .

So, semi major axis, $a=24/2=12$ .

Now, focus of the ellipse is (-7,3).

Let $e$ be the eccentricity of the ellipse,

So, $e=\frac c a$

where $c$ is the distance between the center and focus of the ellipse.

By using the distance formula,

$c=\sqrt{(-9-(-7))^2+(3-3)^2}=2$

$\Rightarrow e=\frac {2}{12}=\frac{1}{6}\;\cdots(ii)$

Again, the relationship among $a,b$ and $e$ is

$e=\sqrt{1-\frac{b^2}{a^2}$

$\Rightarrow \frac{1}{6}=\sqrt{1-\frac{b^2}{(12)^2}$ [from equation (ii)]

$\Rightarrow \frac{1}{36}=\sqrt{1-\frac{b^2}{144}$ [squaring on both the sides]

$\Rightarrow \frac{b^2}{144}=1-\frac{1}{36}$

$\Rightarrow b^2=\frac{35}{36}\times144=140$

So, the value of square of semi-minir axis, $b^2=140$ .

Hence, from equation (i), the equation of required ellipse is standard form is

$\frac{(x-(-9))^2}{144}+\frac{(y-3)^2}{140}=1$

$\Rightarrow \frac{(x+9)^2}{144}+\frac{(y-3)^2}{140}=1$

8 0

2 years ago

A factory produces 30,360 bolts in 12 hours. If the same number of bolts are produced each hour, how many bolts does the factory

drek231 [11]

Answer:

10,120

Step-by-step explanation:

5 0

2 years ago