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marshall27 [118]
3 years ago
11

A bicyclist races on a bicyclist with 13-inch-radius wheels. When she is traveling at a speed of 37 ft/sec, how many revolutions

per minute are her wheels making?
Mathematics
1 answer:
drek231 [11]3 years ago
8 0
Radius of a wheel = 13 inch
= 1.08333 ft
circumference of a wheel = 2×pi×r^2
= 2 × (22/7) × 1.08333^2 ft
= 2 × (22/7) × 1.1736 ft
= (44/7)×1.1736 ft
= 51.6384/7 ft
= 7.3769142857 ft
distance covered in one minute = 37 × 60 ft/min
= 2220 ft/min
now, revolution per minute = 2220 / 7.3769142857
= 300.93884
therefore her wheels are making 300.93884 revolutions per minute
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5. If position of object x = 3 sinΘ – 7 cosΘ then motion of object is bounded between position.​
lesya692 [45]

9514 1404 393

Answer:

  ±√58 ≈ ±7.616

Step-by-step explanation:

The linear combination of sine and cosine functions will have an amplitude that is the root of the sum of the squares of the individual amplitudes.

  |x| = √(3² +7²) = √58

The motion is bounded between positions ±√58.

_____

Here's a way to get to the relation used above.

The sine of the sum of angles is given by ...

  sin(θ+c) = sin(θ)cos(c) +cos(θ)sin(c)

If this is multiplied by some amplitude A, then we have ...

  A·sin(θ+c) = A·sin(θ)cos(c) +A·cos(θ)sin(c)

Comparing this to the given expression, we find ...

  A·cos(c) = 3   and   A·sin(c) = -7

We know that sin²+cos² = 1, so the sum of the squares of these values is ...

  (A·cos(c))² +(A·sin(c))² = A²(cos(c)² +sin(c)²) = A²(1) = A²

That is, A² = (3)² +(-7)² = 9+49 = 58. This tells us the position function can be written as ...

  x = A·sin(θ +c) . . . . for some angle c

  x = (√58)sin(θ +c)

This has the bounds ±√58.

3 0
3 years ago
Name the property of multiplication illustrated<br><br> 112 X 1 = 112
Nat2105 [25]

Answer:

Identity property

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4 0
2 years ago
A long distance phone call between two cities costs $3.43 for 7 minutes. What is the rate in cents per minute?
Evgesh-ka [11]
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4 0
3 years ago
Is the relationship shown by the data linear? If so, model the data with an equation. X:1,5,9,13 Y:5,10,15,20
ryzh [129]
Let
A (x1,y1)-------> (1,5)
B (x2,y2)------> (5,10)
C (x3,y3)------> (9,15)
D (x4,y4)------> (13,20)

find the slope
AB
m=(10-5)/(5-1)-----> m=5/4

find the slope
CB
m=(15-10)/(9-5)-----> m=5/4

find the slope 
DC
m=(20-15)/(13-9)-----> m=5/4

so
<span>the relationship shown is linear
</span>
<span>to model the data with an equation find the equation of a line
</span>with m=5/4 and point A (1,5)
y-y1=m*(x-x1)-----> y-5=(5/4)*(x-1)----> y=1.25x-1.25+5-----> y=1.25x+3.75

the equation to model data is
y=1.25x+3.75

see the attached  figure

3 0
3 years ago
Hello can someone explain this to me please
agasfer [191]
It’s backwards !! So I can’t see what I can help you with
4 0
3 years ago
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