The midpoint of point A and point B is (5, -2.5)
<h3>How to determine the midpoint?</h3>
The coordinates are given as:
A = (3, -8)
B = (7, -3)
The midpoint is calculated as:
(x, y) = 0.5 * (x1 + x2, y1 + y2)
So, we have:
(x, y) = 0.5 * (3 + 7, -8 + 3)
This gives
(x, y) = 0.5 * (10, -5)
Evaluate
(x, y) = (5, -2.5)
Hence, the midpoint of point A and point B is (5, -2.5)
Read more about midpoints at:
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Hey there!
Let's write an equation given this information. We will use x to represent the number.
2(x-7)=5
Now, we use the distributive property to remove the parentheses.
2x-14=5
Now, we add 14 to both sides.
2x=19
We divide both sides by 2.
x=9.5
Therefore, our number is 9.5
I hope this helps!
Are we supposed to find the area? If so, It's 36 because 6 times 6 equals 36 :p Hope I helped.
Answer:
Step-by-step explanation:
We know that:
Only employees are hired during the first 3 days of the week with equal probability.
2 employees are selected at random.
So:
A. The probability that an employee has been hired on a Monday is:
.
If we call P(A) the probability that 2 employees have been hired on a Monday, then:
B. We now look for the probability that two selected employees have been hired on the same day of the week.
The probability that both are hired on a Monday, for example, we know is . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.
So
.
C. If the probability that two people have been hired on a specific day of the week is 
, then the probability that 7 people have been hired on the same day is:
D. The probability is 
. This number is quite close to zero. Therefore it is an unlikely bastate event.
A=1 and 2
B=2 and 4
C=1,2,7 and 14
D=1,2,4,and 8
