Question

Evaluate 8p +3q-188p+3q−188, p, plus, 3, q, minus, 18 when p=\dfrac12p= 2 1 ​ p, equals, start fraction, 1, divided by, 2, end fraction and q=7q=7q, equals, 7.

Answer 1

Given:

The expression is

$8p+3q-18$

To find:

The value of the expression when $p=\dfrac{1}{2}$ and $q=7$.

Solution:

We have,

$8p+3q-18$

Putting $p=\dfrac{1}{2}$ and $q=7$, we get

$8(\dfrac{1}{2})+3(7)-18$

$=4+21-18$

$=7$

Therefore, the value of the expression is 7 when $p=\dfrac{1}{2}$ and $q=7$.