Answer:
The angle formed between CF and the plane ABCD is approximately 47.14°
Step-by-step explanation:
The given parameters are;
BC = 6.8
DE = 9.3
∠BAC = 52°
We note that the angles formed by the vertex of a cuboid are right triangles, therefore, by trigonometric ratios, we get;
sin∠BAC = BC/(The length of a line drawn from A to C)
∴ The length of the line drawn from A to C = BC/sin∠BAC
The length of the line drawn from A to C = 6.8/sin(52°) ≈ 8.63
∴ AC = 8.63
By trigonometry, we have;
The angle formed between CF and the plane ABCD = Angle ∠ACF
In a cuboid, FA = BG = CH = DE = 9.3
The angle formed between CF and the plane ABCD = Angle ∠ACF ≈ 47.14°
Answer:
∠F = 42° to the nearest degree
Step-by-step explanation:
In this question, we are asked to calculate the value of the angle.
Kindly note that since one of the angles we are dealing with in the triangle is 90°, this means that the triangle is a right-angled triangle
Please check attachment for the diagrammatic representation of the triangle
From the diagram, we can identify that the EF is the hypotenuse and the length FG is the adjacent. Thus , the appropriate trigonometric identity to use is the cosine
mathematically;
Cosine of an angle = length of adjacent/length of hypotenuse
F = 42.07
∠F = 42° to the nearest degree
Answer:
Some answers would be 7 6 5 4 3 2 1. Not all numbers will be less than twelve.
Step-by-step explanation:
First, I added the number to 4 that would equal twelve. Then, I just started using numbers below it. If this is a true or false, this would be false because if you added any number (let's say 12) to 4, you might get more than 12. Although, every number in the negatives would work as well, because they didn't state that the absolute value of the number plus 4 is less than 12. Hope it is right!
Answer:
Step-by-step explanation:
In order to solve this problem we must start by graphing the given function and finding the differential area we will use to set our integral up. (See attached picture).
The formula we will use for this problem is the following:
where:
a=0
so the volume becomes:
This can be simplified to:
and the integral can be rewritten like this:
which is a standard integral so we solve it to:
![V=9\pi[tan y]\limits^\frac{\pi}{3}_0](https://tex.z-dn.net/?f=V%3D9%5Cpi%5Btan%20y%5D%5Climits%5E%5Cfrac%7B%5Cpi%7D%7B3%7D_0)
so we get:
![V=9\pi[tan \frac{\pi}{3} - tan 0]](https://tex.z-dn.net/?f=V%3D9%5Cpi%5Btan%20%5Cfrac%7B%5Cpi%7D%7B3%7D%20-%20tan%200%5D)
which yields:
]
Answer:
P'(1, 5)
Step-by-step explanation:
Up 3 is vertical movement, so it changes the y-value: 2 + 3 = 5
Right 4 is horizontal movement, so it changes the x-value: -3 + 4 = 1
