The dimensions of the rectangle will be 6 inches and 12 inches.
<h3>What is the area of the rectangle?</h3>
Let L be the length and W be the width of the rectangle.
Then the area of the rectangle will be
Area of the rectangle = L × W square units
The length of a rectangular poster is 9 more inches than half its width.
L = W/2 + 9
The area of the poster is 72 square inches. Then we have
72 = L × W
72 = (W/2 + 9) × W
144 = (W + 18) × W
144 = W² + 18W
W² + 18W - 144 = 0
Then the factor of the equation will be
W² + 18W - 144 = 0
W² + 24W - 6W - 144 = 0
W(W + 24) - 6(W + 24) = 0
(W + 24)(W - 6) = 0
W = -24, 6
The width of the rectangle is 6 inches. Then the length of the rectangle will be
L = 6/2 + 9
L = 3 + 9
L = 12 inches
The dimensions of the rectangle will be 6 inches and 12 inches.
More about the area of the rectangle link is given below.
brainly.com/question/20693059
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Slope-intercept form: y = mx + b [m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis]
Since you know:
slope(m) = 4
y-intercept(b) = 2 Plug it into the equation
y = mx + b
y = 4x + 2
Your answer would be 135.
This is because angles on a straight line add up to 180°, and so we need to subtract 45 from 180, which gives us 135.
I hope this helps!
Sorry I need the point sheseesg
Time wind time speed divide by 3
