A manufacturer of a consumer electronics products expects 3% of units to fail during the warranty period. A sample of 500 indepe
1 answer:
Answer: a) 0.0000002, b) 15, c) 0.99996.
Step-by-step explanation:
Since we have given that
n = 500
p = 3% = 0.03
q = 1-0.03 = 0.97
So, we will use "Binomial distribution".
(a) What is the probability that none fail during the warranty period?
(b) What is the expected number of failures during the warranty period?
(c) What is the probability that more than 2 units fail during the warranty period?
Hence, a) 0.0000002, b) 15, c) 0.99996.
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Check out the attached image.
Figure 1 moves to figure 2 after the translation rule (x,y) ---> (x+1, y+2)
Figure 2 moves to figure 3 after the rotation 90 degrees clockwise around the origin
Figure 3 moves to figure 4 after the translation rule (x,y) ---> (x+2, y-3)
Figure 4 is in quadrant IV. The size does not change
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Answer: Choice B) Quadrant IV; no
Figure 1 moves to figure 2 after the translation rule (x,y) ---> (x+1, y+2)
Figure 2 moves to figure 3 after the rotation 90 degrees clockwise around the origin
Figure 3 moves to figure 4 after the translation rule (x,y) ---> (x+2, y-3)
Figure 4 is in quadrant IV. The size does not change
-----------------------------------------------
Answer: Choice B) Quadrant IV; no
Given:
The price of a share of stock in JZMobile was $74 two weeks ago.
Seven weeks ago, the price was $59 a share.
To find:
The linear equation to find the price p of a share of JZMobile w weeks from now.
Solution:
Let, p be the price of a share of JZMobile w weeks from now.
The price of a share of stock in JZMobile was $74 two weeks ago. It means, the graph of linear equation passes through (2,74).
Seven weeks ago, the price was $59 a share. It means, the graph of linear equation passes through (7,59).
The graph of linear equation passes through two points (2,74) and (7,59). So, the linear equation is
Adding 74 on both sides, we get
Therefore, the correct option is C.
Answer:
150° and 210°
Step-by-step explanation:
1) to drow a circle with radius=1 in the system of coordinates like in the attached picture;
2) to mark point (-√3/2)≈-0.866 on X-axis (in the picture it is the point M);
3) to graph line AB through point M, the line AB || Y-axis and the points A and B are on the circle with radius=1;
4) to measure the angles ∠ROA and ∠ROB (the points are marked with red colour);
5) finally, m(∠ROA)=150°; m(∠ROB)=210°.
