The given function are
r(x) = 2 - x² and w(x) = x - 2
<span>(w*r)(x) can be obtained by multiplying the both function together
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So, <span>(w*r)(x) = w(x) * r(x) = (x-2)*(2-x²)</span>
<span>(w*r)(x) = x (2-x²) - 2(2-x²)</span>
= 2x - x³ - 4 + 2x²
∴ <span>
(w*r)(x) = -x³ + 2x² + 2x - 4</span>
<span>It is a polynomial function with a domain equal to R
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The range of <span>(w*r)(x) can be obtained by graphing the function
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To graph (w*r)(x), we need to make a table between x and (w*r)(x)
See the attached figure which represents the table and the graph of <span>(w*r)(x)
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As shown in the graph the range of <span>
(w*r)(x) is (-∞,∞)</span>
2x2+2x-1=
4+2(-3)-1=
4+(-6)-1=
4+(-7)=
-3
Answer:
A
Step-by-step explanation:
Perpendicular lines have a relationship between their slopes. Their slope are negative inverses of each other. This means is one is 3 then the negative reciprocal is the other or -1/3. The slope here is 1/9 so the perpendicular slope is -9. Slope is always attached to the x term so A is the solution.
Step-by-step explanation:
We can construct a unique equilateral triangle if we know <u>it's one</u><u> </u><u>side</u><u>.</u>
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my own answer
Is equal to 9.4 you're welcome