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Juli2301 [7.4K]
3 years ago
5

Find the GCF of 15y^3 and -20y. Please explain how to do this type of problem. Thanks!

Mathematics
2 answers:
Rina8888 [55]3 years ago
6 0

Answer:

5y

Step-by-step explanation:

First find all the factors of 15y^3 and then all the factors of -20y

15y^3 = 3 , 5 , y,  y,  y

-20y = 2 , 4,  5, 10, y

The GCF is 5 and y. We choose 5 because it is the greatest number and common in both sets. We also choose one y because it is common in both sets and one y is the greatest common y.

Answer = 5y

You can also do this by using the prime factorization method.

Fittoniya [83]3 years ago
4 0

Answer:

GCF will be 5y

Step-by-step explanation:

First of all the negative signs will be excluded when finding the GCF. The GCF is calculated by multiplying together the highest power of each of the common factors.

15^3 can be split into,

3*5*y*y*y.

-20y into,

2*4*5*10*y.

We will choose 5 as it is the greatest common number in both sets and choose y as it is also common in both sets.

So, the GCF will be 5y.

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Solve for w k=2b-5w/3k
nlexa [21]
k = \frac{2b - 5w}{3k}
3k^{2} = 2b - 5w
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7 0
3 years ago
Read 2 more answers
Solve for x use the completing the square method x^2+6x=5
Mrac [35]

Answer:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

Step-by-step explanation:

x^{2}+6x-5=0

we divide the coefficient of the X by half :

in this case: 6/2 = 3 , then we do the following

The result obtained is raised to square power:  3^2=9

we sum and subtract by 9 to maintain the balance of the equation:

x^{2}+6x+9-9-5=0

we have:

(x+3)^{2}-9-5=0

(x+3)^{2} = 14

lets apply square root on both sides of the equation:

\sqrt{(x+3)^{2}}=\sqrt{14}

we know:

\sqrt{a^{2}} = abs(a)

so we have:

abs(x+3)=\sqrt{14}

from where two solutions are obtained

x_{1} + 3 =\sqrt{14} \\\\x_{2} + 3 =-\sqrt{14}

finally we have:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

5 0
3 years ago
Read 2 more answers
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