Answer:
B. The approximate length of EF is 4.47 units, and the approximate perimeter of triangle EFG is 12.94 units.
Step-by-step explanation:
First step is to determine the length of EF, since that will give us 2 sides of the triangle (since EG = EF).
From the diagram, we can easily make a rectangle triangle by dropping a vertical line from vertex E, let's name Z the meeting point of that line with the segment GF. Then we have a rectangle triangle EZF with a height of 4 and a base of 2, of which EF is the hypotenuse. So...
EF² = 4² + 2² = 16 + 4 = 20
EF = √20 = 4.47
Now that we have EF, we also have EG:
EF = 4.47
EG = 4.47
GF = 4 (visible on the graph)
Perimeter = 4.47 + 4.47 + 4 = 12.94 units.
The point P has coordinates (x,y) = (-2,6) so x = -2 and y = 6
Replace x and y with those values into the rule given
So,
(x,y) ---> (x-2, y-16)
turns into
(-2,6) ---> (-2-2, 6-16) = (-4,-10)
P = (-2,6)
P ' = (-4,-10)
The answer is -10 because your teacher just wants the y coordinate of point P'
Answer:
444
Step-by-step explanation:
$55 this is shown by doing 80/100=0.80. and 0.80*55=this is the answer
The given quadrilateral is a kite.
Given: Point A (2, 4), B (-2, -5), C (7, -1) and D (7, 4)
Firstly, we find the distance between AD and DC
AD = 
⇒ AD = 
⇒ AD = 5
DC = 
⇒ DC =
⇒ DC = 5
Hence, AD = DC = 5
Now, find the distance between AB and BC
AB = 
⇒ AB = 
⇒ AB = 
⇒ AB = 
BC = 
⇒ BC = 
⇒ BC = 
⇒ BC =
Hence, AB = BC = √97
In the given quadrilateral, the two pair is of equal length and these sides are adjacent to each other.
Hence, it follows the property of kite.
For more questions on quadrilateral, visit:
brainly.com/question/23935806
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