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3 years ago

Please help me on this

Mathematics

1 answer:

Alex777 [14]3 years ago

6 0

Answer:

$x^3-9x^2+28x-60$

Step-by-step explanation:

$(x-5)(x+2)(x-6) = (x^2-3x+10)(x-6) = x^3-9x^2+28x-60$

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The trifecta at most racetracks consists of selecting the first-, second-, and third-place finishers in a particular race in t

ziro4ka [17]

The total tickets to be purchased to guarantee the win = 504 tickets

Step-by-step explanation:

Step 1 :

Number of entries in the trifecta race = 9

The win is to select the first finisher, second finisher and third finisher in their proper order.

We need to find the number of tickets to be purchased to guarantee the win

Step 2 :

Number of ways to select the first finisher = 9

Number of ways to select the second finisher = 8 [the first is selected and fixed. So the number of available finishes is reduced by 1]

Number of ways to select the third finisher = 7

Hence the total tickets to be purchased to guarantee the win = 9 × 8 × 7 = 504

Step 3 :

Answer :

The total tickets to be purchased to guarantee the win = 504 tickets

3 0

3 years ago

Brittney made a proportional copy of a figure by multiplying each side length by 1/4. Drag numbers to complete the table

bonufazy [111]

Answer:

Step-by-step explanation:

Side Original length Copy length $\frac{Original length}{Copy length}$

a 4 1 $\frac{4}{1}=4$

b 6 1.5 $\frac{6}{1.5}=4$

c 20 5 $\frac{20}{5}=4$

d 16 4 $\frac{16}{4}=4$

4 0

3 years ago

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Evaluate the integral using the indicated trigonometric substitution. (use c for the constant of integration.) x^3 / sqrt x^2 +

slava [35]

$\displaystyle\int\frac{x^3}{\sqrt{x^2+49}}\,\mathrm dx$

Taking $x=7\tan\theta$ gives $\mathrm dx=7\sec^2\theta\,\mathrm d\theta$ , so that the integral becomes

$\displaystyle\int\frac{(7\tan\theta)^3}{\sqrt{(7\tan\theta)^2+49}}(7\sec^2\theta)\,\mathrm d\theta$
$=\displaystyle7^4\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{49\tan^2\theta+49}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{\tan^2\theta+1}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{\sec^2\theta}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{|\sec\theta|}\,\mathrm d\theta$

When $\sec\theta>0$ , we have

$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sec\theta}\,\mathrm d\theta$
$=\displaystyle7^3\int\tan^3\theta\sec^2\theta\,\mathrm d\theta$

and from here we can substitute $u=\tan\theta$ to proceed from here.

Quick note: When we set $x=7\tan\theta$ , we are implicitly enforcing $-\dfrac\pi2$ just so that the substitution can be undone later via $\theta=\tan^{-1}\dfrac x7$ . But note that over this domain, we automatically guarantee that $\sec\theta>0$ , so the absolute value bars can be dropped immediately.

6 0

3 years ago

Answer the questions below (20 Points)

Volgvan

Answer: for the 12,13,40,95,88,7,95

mean 95,median 83,mode 95

Step-by-step explanation:

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3 years ago

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Sweet T has 2 orange picks for every 5 green. If there are 12 picks in all how many picks are orange

e-lub [12.9K]